Question

我有两个numpy.ndarray

[[' THE OLD TESTAMENT ']
[' SEAN SONG ']
[' CITY WALK ']]

和

[[' This is the name of an Old Testament ']
 [' Hello this is great ']
[' Wait the way you are doing ']]

我想将这些ndarray转换成字典。

 {
"THE OLD TESTAMENT": "This is the name of an Old Testament",
"SEAN SONG": "Hello this is great",
"CITY WALK": Wait the way you are doing 
 }

我正在使用下面编写的代码

keys = df.as_matrix()
print (keys)
values = df1.as_matrix()
print (values)
new_dict = dict(izip(keys, values))

Answer 1

不必转换为arrays，请使用Android Documentation of Bundle Tool和zip选择第一列：

new_dict = dict(zip(df.iloc[:, 0], df1.iloc[:, 0]))

或按名称选择列：

new_dict = dict(zip(df['col'], df1['col']))

Answer 2

先压缩数组：

In [1]: import numpy as np

In [2]: keys = np.array(
   ...:     [[' THE OLD TESTAMENT '],
   ...:     [' SEAN SONG '],
   ...:     [' CITY WALK ']]
   ...: )

In [3]: values = np.array(
   ...:     [[' This is the name of an Old Testament '],
   ...:      [' Hello this is great '],
   ...:     [' Wait the way you are doing ']]
   ...: )

In [4]: dict(zip(keys.squeeze(), values.squeeze()))
Out[4]:
{' CITY WALK ': ' Wait the way you are doing ',
 ' SEAN SONG ': ' Hello this is great ',
 ' THE OLD TESTAMENT ': ' This is the name of an Old Testament '}

或仅使用切片：

In [5]: dict(zip(keys[:,0], values[:,0]))
Out[5]:
{' CITY WALK ': ' Wait the way you are doing ',
 ' SEAN SONG ': ' Hello this is great ',
 ' THE OLD TESTAMENT ': ' This is the name of an Old Testament '}

Answer 3

keyh=[[' THE OLD TESTAMENT '],
[' SEAN SONG '],
[' CITY WALK ']]

valueh=[[' This is the name of an Old Testament '],
 [' Hello this is great '],
[' Wait the way you are doing ']]

dictionary = dict(zip([item[0] for item in keyh], [item[0] for item in valueh]))

输出

{
"THE OLD TESTAMENT": "This is the name of an Old Testament",
"SEAN SONG": "Hello this is great",
"CITY WALK": "Wait the way you are doing"
 }

Answer 4

keys = [[' THE OLD TESTAMENT '],[' SEAN SONG '],[' CITY WALK ']]

values = [[' This is the name of an Old Testament '], [' Hello this is great '],[' Wait the way you are doing ']]


keys = [x[0] for x in keys]

values = [x[0] for x in values]


dictionary = dict(zip(keys, values))

创建两个numpy.ndarray的字典？

4 个答案: