Question

lst = ['Cam218-10-03_16-05-21-54.jpg',     
       'Cam318-10-03_17-04-21-54.jpg',
       'Cam418-10-03_16-04-21-54.jpg',  
       'Cam218-10-02_16-05-21-54.jpg',
       'Cam318-10-02_17-04-21-54.jpg',  
       'Cam418-10-02_16-04-21-54.jpg',
       'Cam218-10-02_16-04-08-31.jpg',  
       'Cam318-10-02_16-04-08-30.jpg', 
       'Cam418-10-02_16-04-08-30.jpg',  
       'Cam518-10-02_16-04-08-35.jpg',
       'Cam618-10-02_16-04-08-36.jpg',  
       'Cam118-10-02_16-04-09-33.jpg', 
       'Cam218-10-02_16-04-09-33.jpg',  
       'Cam318-10-02_16-04-09-33.jpg', 
       'Cam418-10-02_16-04-09-33.jpg',  
       'Cam518-10-02_16-04-09-33.jpg',
       'Cam618-10-02_16-04-09-33.jpg',  
       'Cam118-10-02_16-04-11-53.jpg', 
       'Cam218-10-02_16-04-11-53.jpg',  
       'Cam318-10-02_16-04-11-53.jpg', 
       'Cam418-10-02_16-04-08-30.jpg',  
       'Cam118-10-02_16-04-08-31.jpg', 
       'Cam518-10-02_16-04-11-53.jpg',  
       'Cam118-10-02_16-04-11-53.jpg']

从此列表中，我需要输出：

['Cam118-10-02_16-04-08-31.jpg',
 'Cam218-10-02_16-04-08-31.jpg',
 'Cam318-10-02_16-04-08-30.jpg', 
 'Cam418-10-02_16-04-08-30.jpg',
 'Cam518-10-02_16-04-08-35.jpg',
 'Cam618-10-02_16-04-08-36.jpg']

通过使用Python。有人可以帮我吗？

Answer 1

使用itertools.groupby-O（n * log（n））

>>> from itertools import groupby
>>> [next(g) for _, g in groupby(sorted(lst), key=lambda cam: cam.partition('-')[0])]
['Cam118-10-02_16-04-08-31.jpg',
 'Cam218-10-02_16-04-08-31.jpg',
 'Cam318-10-02_16-04-08-30.jpg',
 'Cam418-10-02_16-04-08-30.jpg',
 'Cam518-10-02_16-04-08-35.jpg',
 'Cam618-10-02_16-04-08-36.jpg']

手动跟踪重复项（输出未排序，但可能对其他读者有用）-O（n）

>>> seen = set()
>>> result = []
>>> 
>>> for cam in lst:
...:    model, *_ = cam.partition('-')
...:    if model not in seen:
...:        result.append(cam)
...:        seen.add(model)
...:        
>>> result
['Cam218-10-03_16-05-21-54.jpg',
 'Cam318-10-03_17-04-21-54.jpg',
 'Cam418-10-03_16-04-21-54.jpg',
 'Cam518-10-02_16-04-08-35.jpg',
 'Cam618-10-02_16-04-08-36.jpg',
 'Cam118-10-02_16-04-09-33.jpg']

Answer 2

您可以在对列表进行排序后确定是否有条件检查photo标签的出现情况

list.sort()
i = 1
for item in list:
    if(item[3]==str(i)):
        i=i+1
        print(item)
        continue

结果是

Cam118-10-02_16-04-08-31.jpg
Cam218-10-02_16-04-08-31.jpg
Cam318-10-02_16-04-08-30.jpg
Cam418-10-02_16-04-08-30.jpg
Cam518-10-02_16-04-08-35.jpg
Cam618-10-02_16-04-08-36.jpg

如果您想获得与项目顺序无关的第一个项目，则删除list.sort（）将解决该问题。

如何从列表中分离cam1,2,3,4,5,6首张图像

2 个答案: