表如下。
CREATE TABLE `departments` (
department_id INT(2) NOT NULL AUTO_INCREMENT,
department_name VARCHAR(30) NOT NULL,
total_employees INT(4),
PRIMARY KEY (department_id),
UNIQUE (department_name));
CREATE TABLE `employees` (
employee_id INT(4) NOT NULL AUTO_INCREMENT,
employee_email VARCHAR(30) NOT NULL,
employee_first_name VARCHAR(30) NOT NULL,
employee_last_name VARCHAR(30) NOT NULL,
department_name VARCHAR(30) NOT NULL,
PRIMARY KEY (employee_id),
UNIQUE (employee_email),
FOREIGN KEY (department_name)
REFERENCES departments (department_name)
ON DELETE CASCADE);
这是触发器,我希望它显示每个部门的员工总数。
delimiter $$
create trigger department_wise_total_employee_counting
after insert on employees
for each row begin update departments set total_employees=total_employees+1
where department_id=department_id; end$$ delimiter ;
INSERT INTO `departments`
VALUES
(1,'HRM',0),(2,'Accounting',0);
INSERT INTO `employees`
VALUES
(1,'bh@gmail.com','A','B','HRM'),
(2,'ak@gmail.com','C','D','HRM'),
(3,'mr@gmail.com','E','F','HRM'),
(4,'pr@gmail.com','G','H','Accounting');
运行以下查询时:
select * from departments;
我正在尝试使HRM的total_employees = 3,而会计部门的total_employees = 1。 将不胜感激任何建议。
答案 0 :(得分:2)
正如@ P.Salmon所指出的那样,通常您不应存储可以轻松计算的数据。对于此应用程序,VIEW
(由@TamilSelvanC建议)是一个很好的解决方案。例如:
CREATE VIEW departments_view AS
SELECT d.department_id, d.department_name, COUNT(e.employee_id) AS total_employees
FROM departments d
LEFT JOIN employees e ON e.department_name = d.department_name
GROUP BY d.department_id;
SELECT * FROM departments_view
输出:
department_id department_name total_employees
1 HRM 3
2 Accounting 1
3 Engineering 0