Question

我正在废弃板球比赛的详细信息，现在我已经测试了结果，我想将其保存在文件中。在将html保存到文件中时，我得到了str object cannot be interedpreted as an integer

这是我的代码

for i in range(0, 2000):
    url = 'http://search.espncricinfo.com/ci/content/match/search.html?search=test;all=1;page=%s' %i
    html = requests.get(url)

    print ('Checking page %s of 2000' %(i+1))

    soupy = bs4.BeautifulSoup(html.text, 'html.parser')

    time.sleep(1)
    for new_host in soupy.findAll('a', {'class' : 'srchPlyrNmTxt'}):
        try:
            new_host = new_host['href']
        except:
            continue
        odiurl = BASE_URL + new_host
        new_host = odiurl
        print(new_host)
        html = requests.get(new_host).text
        with open('espncricinfo-fc/{0!s}'.format(str.split(new_host, "/")[4]), "wb") as f:
                f.write(html)

我收到此错误str object cannot be interedpreted as an integer

此行出现错误

，以open（'espncricinfo-fc / {0！s}'。format（str.split（new_host，“ /”）[4]），“ wb”）as f： < / p>

Answer 1

如果您使用的是Python 3.x，请尝试将最后一行更改为

new_host = str(new_host['href'])

也可以尝试一下

[root@ip-10-0-1-13]# kubectl config current-context
kubernetes-admin@kubernetes

Answer 2

问题是您的print语句。它应该显示为

print('checking %d etc.' % (i + 1))

'str'对象不能在python中解释为整数

2 个答案: