t_syntaxTree
是一种结构,定义为:
typedef struct t_syntaxTree {
char nodeName[16];
int nodesLen;
struct t_syntaxTree** nodes;
} t_syntaxTree;
我编写了函数treeToStr
来转换字符串中的语法树,该代码应该可以自我解释。输出字符串格式类似于Lisp,例如,输出字符串可以为(or (and true true) (> b 3))
。
以下代码可以工作,但是如果我使用valgrind执行程序,则会因分段错误而崩溃。
此外,在崩溃之前,valgrind告诉我我的一些realloc调用无效。
int recTreeToStr(t_syntaxTree* t, char* str, int len) {
if (t->nodesLen == 0) {
int nLen = len + strlen(t->nodeName);
str = realloc(str, sizeof(char) * nLen);
strcat(str, t->nodeName);
return nLen;
}
else {
int nLen = len + strlen(t->nodeName) + 1;
str = realloc(str, sizeof(char) * nLen);
strcat(str, "(");
strcat(str, t->nodeName);
for (int i=0; i<t->nodesLen; i++) {
nLen++;
str = realloc(str, sizeof(char) * nLen);
strcat(str, " ");
nLen = recTreeToStr(t->nodes[i], str, nLen);
}
nLen++;
str = realloc(str, sizeof(char) * nLen);
strcat(str, ")");
return nLen;
}
}
char* treeToStr(t_syntaxTree* tree) {
char* str=malloc(sizeof(char));
str[0] = '\0';
recTreeToStr(tree, str, 1);
return str;
}
这是崩溃之前的valgrind报告(此消息之后,程序立即崩溃并出现分段错误):
==26561== Invalid free() / delete / delete[] / realloc()
==26561== at 0x4839D7B: realloc (vg_replace_malloc.c:826)
==26561== by 0x10B3C4: recTreeToStr (cooper.c:443)
==26561== by 0x10B420: recTreeToStr (cooper.c:445)
==26561== by 0x10B420: recTreeToStr (cooper.c:445)
==26561== by 0x10B420: recTreeToStr (cooper.c:445)
==26561== by 0x10B4C0: treeToStr (cooper.c:459)
==26561== by 0x10B4F2: cooper (cooper.c:467)
==26561== by 0x10922E: main (test.c:6)
==26561== Address 0x4a6aee0 is 0 bytes inside a block of size 15 free'd
==26561== at 0x4839D7B: realloc (vg_replace_malloc.c:826)
==26561== by 0x10B310: recTreeToStr (cooper.c:431)
==26561== by 0x10B420: recTreeToStr (cooper.c:445)
==26561== by 0x10B420: recTreeToStr (cooper.c:445)
==26561== by 0x10B420: recTreeToStr (cooper.c:445)
==26561== by 0x10B420: recTreeToStr (cooper.c:445)
==26561== by 0x10B4C0: treeToStr (cooper.c:459)
==26561== by 0x10B4F2: cooper (cooper.c:467)
==26561== by 0x10922E: main (test.c:6)
==26561== Block was alloc'd at
==26561== at 0x4839D7B: realloc (vg_replace_malloc.c:826)
==26561== by 0x10B3C4: recTreeToStr (cooper.c:443)
==26561== by 0x10B420: recTreeToStr (cooper.c:445)
==26561== by 0x10B420: recTreeToStr (cooper.c:445)
==26561== by 0x10B420: recTreeToStr (cooper.c:445)
==26561== by 0x10B4C0: treeToStr (cooper.c:459)
==26561== by 0x10B4F2: cooper (cooper.c:467)
==26561== by 0x10922E: main (test.c:6)
==26561==
==26561== Invalid read of size 1
==26561== at 0x10B3DF: recTreeToStr (cooper.c:444)
==26561== by 0x10B420: recTreeToStr (cooper.c:445)
==26561== by 0x10B420: recTreeToStr (cooper.c:445)
==26561== by 0x10B420: recTreeToStr (cooper.c:445)
==26561== by 0x10B4C0: treeToStr (cooper.c:459)
==26561== by 0x10B4F2: cooper (cooper.c:467)
==26561== by 0x10922E: main (test.c:6)
==26561== Address 0x0 is not stack'd, malloc'd or (recently) free'd
==26561==
==26561==
==26561== Process terminating with default action of signal 11 (SIGSEGV): dumping core
==26561== Access not within mapped region at address 0x0
==26561== at 0x10B3DF: recTreeToStr (cooper.c:444)
==26561== by 0x10B420: recTreeToStr (cooper.c:445)
==26561== by 0x10B420: recTreeToStr (cooper.c:445)
==26561== by 0x10B420: recTreeToStr (cooper.c:445)
==26561== by 0x10B4C0: treeToStr (cooper.c:459)
==26561== by 0x10B4F2: cooper (cooper.c:467)
==26561== by 0x10922E: main (test.c:6)
==26561== If you believe this happened as a result of a stack
==26561== overflow in your program's main thread (unlikely but
==26561== possible), you can try to increase the size of the
==26561== main thread stack using the --main-stacksize= flag.
==26561== The main thread stack size used in this run was 8388608.
==26561==
==26561== HEAP SUMMARY:
==26561== in use at exit: 1,249 bytes in 46 blocks
==26561== total heap usage: 224 allocs, 178 frees, 21,257 bytes allocated
==26561==
==26561== 17 bytes in 1 blocks are definitely lost in loss record 2 of 11
==26561== at 0x4839D7B: realloc (vg_replace_malloc.c:826)
==26561== by 0x10B310: recTreeToStr (cooper.c:431)
==26561== by 0x10B420: recTreeToStr (cooper.c:445)
==26561== by 0x10B420: recTreeToStr (cooper.c:445)
==26561== by 0x10B420: recTreeToStr (cooper.c:445)
==26561== by 0x10B420: recTreeToStr (cooper.c:445)
==26561== by 0x10B4C0: treeToStr (cooper.c:459)
==26561== by 0x10B4F2: cooper (cooper.c:467)
==26561== by 0x10922E: main (test.c:6)
==26561==
==26561== LEAK SUMMARY:
==26561== definitely lost: 17 bytes in 1 blocks
==26561== indirectly lost: 0 bytes in 0 blocks
==26561== possibly lost: 0 bytes in 0 blocks
==26561== still reachable: 1,232 bytes in 45 blocks
==26561== suppressed: 0 bytes in 0 blocks
==26561== Reachable blocks (those to which a pointer was found) are not shown.
==26561== To see them, rerun with: --leak-check=full --show-leak-kinds=all
==26561==
==26561== For counts of detected and suppressed errors, rerun with: -v
==26561== ERROR SUMMARY: 3 errors from 3 contexts (suppressed: 0 from 0)
答案 0 :(得分:2)
首次致电realloc
后,您释放了str
。它已被新分配代替。然后,您的函数将返回,而不会在任何地方存储str
的新值。
是的,您是在str
返回后使用recTreeToStr
的无效值。
答案 1 :(得分:1)
要成功重新分配char *,实际上您需要传递char **。您的方法中的char *是您认为要重新分配的真实指针的副本。
类似的东西:
int recTreeToStr(t_syntaxTree* t, char** str, int len) {
...
*str = realloc(*str, sizeof(char) * nLen);
...
}
和
recTreeToStr(tree, &str, 1);
我还担心您正在为现有字符串+节点名称的长度分配内存,但同时还包括'('和')'和'',而没有为它们分配空间。 (除非我是盲人。)