我正在使用dateutil.relativedelta来计算年龄。在某些情况下,我正在验证结果,这是不正确的。仅当开始日期的日期为1,月份的结束日期为31,而不是所有这些月份时,才会发生此问题!奇怪的是,一月和八月的结果是正确的。我肯定丢失了一些东西,但是无法查明是什么地方。
我在Win32和dateutil 2.7.5上使用python 2.7.10(但与2.6.1相同)
要运行的代码:
from __future__ import print_function
import datetime
from dateutil.relativedelta import relativedelta
# Main function -- later on, its result is used in dateutil.rrule
# (all irrelevant code expurged)
def age(start, end, includeFirstDay=False):
# includeFirstDay: whether to include the start date in the result
if includeFirstDay:
start += relativedelta(days=-1)
# Documentation tells nothing about the order of arguments when the first
# two are dates. The following seems correct.
return relativedelta(end, start)
# Utility in external module
def eomonth(dt):
# from the beginning of month, add one month and substract one day
eom = dt + relativedelta(days=-dt.day+1) + relativedelta(months=+1, days=-1)
return eom
test_values = [
# the 3 following lines fail
(datetime.date(2018, 10, 1), datetime.date(2018, 10, 31)),
(datetime.date(2018, 10, 1), datetime.date(2018, 11, 1)+relativedelta(days=-1)),
(datetime.date(2018, 10, 1), eomonth(datetime.date(2018, 10, 1))),
# the following lines pass
(datetime.date(2018, 10, 5), eomonth(datetime.date(2018, 10, 5))),
(datetime.date(2016, 2, 1), datetime.date(2016, 2, 29)),
(datetime.date(2016, 2, 1), datetime.date(2016, 3, 1)+relativedelta(days=-1)),
(datetime.date(2016, 2, 1), eomonth(datetime.date(2016, 2, 1))),
]
def test(start, end, includeFirstDay=False):
rd = age(start, end, includeFirstDay=includeFirstDay)
# calculate end date from age
d = rd.days + (-1 if includeFirstDay else 0)
fin = start + relativedelta(years=rd.years, months=rd.months, days=d)
if fin != end: # i.e. AssertionError
print('expected %s, got %s (includeFirstDay=%s)' %(end, fin, includeFirstDay))
for start, end in test_values:
test(start, end, includeFirstDay=False)
test(start, end, includeFirstDay=True)
# trying with all months in a year
def make_test(year):
t = []
for month in range(1, 13):
start = datetime.date(year, month, 1)
# Three ways to find the end of the month
t.append((start, eomonth(start)))
t.append((start, start + relativedelta(months=+1, days=-1))) # only if start day == 1
for eom in [31, 30, 29, 28]: # brute force
try:
t.append((start, datetime.date(year, month, eom)))
break
except:
pass
return sorted(list(set(t)))
from pprint import pprint
print('\n*** testing 2016 (leap year)')
test_values = make_test(2016)
pprint(test_values) # verify ends of months are correct
for start, end in test_values:
test(start, end, includeFirstDay=False)
test(start, end, includeFirstDay=True)
print('\n*** testing 2017')
test_values = make_test(2017)
pprint(test_values) # verify ends of months are correct
for start, end in test_values:
test(start, end, includeFirstDay=False)
test(start, end, includeFirstDay=True)
输出:
expected 2018-10-31, got 2018-11-01 (includeFirstDay=True)
expected 2018-10-31, got 2018-11-01 (includeFirstDay=True)
expected 2018-10-31, got 2018-11-01 (includeFirstDay=True)
*** testing 2016 (leap year)
[(datetime.date(2016, 1, 1), datetime.date(2016, 1, 31)),
(datetime.date(2016, 2, 1), datetime.date(2016, 2, 29)),
(datetime.date(2016, 3, 1), datetime.date(2016, 3, 31)),
(datetime.date(2016, 4, 1), datetime.date(2016, 4, 30)),
(datetime.date(2016, 5, 1), datetime.date(2016, 5, 31)),
(datetime.date(2016, 6, 1), datetime.date(2016, 6, 30)),
(datetime.date(2016, 7, 1), datetime.date(2016, 7, 31)),
(datetime.date(2016, 8, 1), datetime.date(2016, 8, 31)),
(datetime.date(2016, 9, 1), datetime.date(2016, 9, 30)),
(datetime.date(2016, 10, 1), datetime.date(2016, 10, 31)),
(datetime.date(2016, 11, 1), datetime.date(2016, 11, 30)),
(datetime.date(2016, 12, 1), datetime.date(2016, 12, 31))]
expected 2016-03-31, got 2016-04-02 (includeFirstDay=True)
expected 2016-05-31, got 2016-06-01 (includeFirstDay=True)
expected 2016-07-31, got 2016-08-01 (includeFirstDay=True)
expected 2016-10-31, got 2016-11-01 (includeFirstDay=True)
expected 2016-12-31, got 2017-01-01 (includeFirstDay=True)
*** testing 2017
[(datetime.date(2017, 1, 1), datetime.date(2017, 1, 31)),
(datetime.date(2017, 2, 1), datetime.date(2017, 2, 28)),
(datetime.date(2017, 3, 1), datetime.date(2017, 3, 31)),
(datetime.date(2017, 4, 1), datetime.date(2017, 4, 30)),
(datetime.date(2017, 5, 1), datetime.date(2017, 5, 31)),
(datetime.date(2017, 6, 1), datetime.date(2017, 6, 30)),
(datetime.date(2017, 7, 1), datetime.date(2017, 7, 31)),
(datetime.date(2017, 8, 1), datetime.date(2017, 8, 31)),
(datetime.date(2017, 9, 1), datetime.date(2017, 9, 30)),
(datetime.date(2017, 10, 1), datetime.date(2017, 10, 31)),
(datetime.date(2017, 11, 1), datetime.date(2017, 11, 30)),
(datetime.date(2017, 12, 1), datetime.date(2017, 12, 31))]
expected 2017-03-31, got 2017-04-03 (includeFirstDay=True)
expected 2017-05-31, got 2017-06-01 (includeFirstDay=True)
expected 2017-07-31, got 2017-08-01 (includeFirstDay=True)
expected 2017-10-31, got 2017-11-01 (includeFirstDay=True)
expected 2017-12-31, got 2018-01-01 (includeFirstDay=True)
此外,3月的结束日期如果可能的话(甚至存在)是错误的。
如果有人能启发我,将不胜感激。预先感谢。
答案 0 :(得分:1)
from __future__ import print_function
import datetime
from datetime import date
from dateutil.relativedelta import relativedelta
today= date.today()
end_day=today.replace(day=1)
end_day += relativedelta(months=1)
end_day -= relativedelta(days=1)
print(end_day)
答案 1 :(得分:1)
我的函数age() 写得不好。这是正确的:
def age(start, end, includeFirstDay=False):
r = relativedelta(end, start)
if includeFirstDay:
r += relativedelta(days=1)
return r
说明:将 start
偏移 -1 天将日期移至上个月,并欺骗了对我的意图感到困惑的相对增量。
答案 2 :(得分:0)
实际上,我做错了。 一月和八月表现“正常”的原因:在这些月份中,前几个月也有31天。 三月对我来说看起来很奇怪的原因:二月比31天少2或3天
例如:
start = datetime.date(2018, 3, 1)
end = start + relativedelta(months=+1, days=-1)
a = age(start, end, True)
print 'start:', start
print 'end :', end
print 'age :', a
输出:
start: 2018-03-01
end : 2018-03-31
age : relativedelta(months=+1, days=+3)
我期待的是诸如relativedelta(days = + 31)之类的东西。
根据提供的开始日期和结束日期, relativedelta 返回不同的结果。例子:
relativedelta(datetime.date(2018, 4, 1), datetime.date(2018, 3, 1))
给予
relativedelta(months=+1)
和
relativedelta(datetime.date(2018, 3, 31), datetime.date(2018, 2, 28))
给予
relativedelta(months=+1, days=+3)
无论如何完成,开始日期和结束日期之间的差值应始终等于31天。
我的结论是,在计算日期中的一个日期的第一天和最后一天(包括所有天)之间,不使用相对增量来计算年龄。
或者修改我可能会做的函数age()。
编辑
在不久的将来,我将删除此问题,因为我认为它提出的要点应包括在datecorn文档的“拐角案例”类别中。