我在下拉值更改jquery方法是上调用jquery函数,
function MyFunction() {
alert($('#DDlSurvey').val());
$.ajax({
url: "@Url.Action("GetSelectedQuestion", "ConductSurveyController")",
data: { prefix: $('#DDlSurvey').val() },
type: "GET",
dataType: "json",
success: function (data) {
// loadData(data);
alert(data)
alert("Success");
},
error: function () {
alert("Failed! Please try again.");
}
});
//$('#YourLabelId').val('ReplaceWithThisValue');
}
</script>
我正在调用的函数,并且正在接收下拉值警报
现在,我正在调用的函数是控制器“ GetSelectedQuestion
”中的“ ConductSurveyController
”
方法就像,
[HttpPost]
public JsonResult GetSelectedQuestion(int prefix)
{
List<SelectList> Questions=new List<SelectList>();
// Here "MyDatabaseEntities " is dbContext, which is created at time of model creation.
SurveyAppEntities ObjectSur = new SurveyAppEntities();
// Questions = ObjectSur.Surveys.Where(a => a.ID.Equals(prefix)).toToList();
由于出现错误,我不认为此方法正在调用
“
Failed! Please try again
”
从我的脚本开始。
希望获得您的建议
谢谢
var e = from q in ObjectSur.Questions
join b in ObjectSur.SurveyQuestions on q.ID equals b.QuestionID where b.SurveyID.Equals(prefix)
select q ;
return new JsonResult { Data = e, JsonRequestBehavior = JsonRequestBehavior.AllowGet };
}
答案 0 :(得分:1)
您的控制器中的方法用select convert(date,
stuff(datestr, 1, charindex(',', datestr) + 1, '')
)
from (values ('Wednesday, November 21, 2018')) v(datestr)
装饰,而在ajax中,您将请求的类型指定为HttpPost
。您可以更改方法,使其像这样:
get
或更改您的请求类型以在您的Ajax调用中发布:
[HttpGet]
public JsonResult GetSelectedQuestion(int prefix)
{
}
此外,$.ajax({
url: "@Url.Action("GetSelectedQuestion", "ConductSurveyController")",
data: { prefix: $('#DDlSurvey').val() },
type: "Post",
在Controller
中是多余的,您需要将其删除并简单地将其称为ConductSurveyController
:
ConductSurvey
答案 1 :(得分:1)
我认为您正在直接使用控制器名称。您的Ajax代码就是这样。
Sub findValue()
Dim xlRange As Range
Dim xlCell As Range
Dim xlSheet As Worksheet
Dim valueToFind
For Each cell In Range("h2:h8")
cell.Select
cell = ActiveCell
MsgBox (cell)
valueToFind = ActiveCell
Set xlSheet = ActiveWorkbook.Worksheets("DATA")
Set xlRange = xlSheet.Range("A1:A13")
For Each xlCell In xlRange
If xlCell.Value = valueToFind Then
MsgBox (xlCell.Offset(0, 1).Value)
valueToFind.Offset(0, 2).Value = xlCell.Offset(0, 1).Value
End If
Next xlCell