Question

我的文件夹中有一些csv文件，我试图删除所有空白行，并将新闻文件移到新文件夹中。

这是我的代码：

import csv
import glob
import os
import shutil

path = 'in_folder/*.csv'
files=glob.glob(path)

#Read every file in the directory

x = 0 #counter

for filename in files:

    with open(filename, 'r') as fin:
        data = fin.read().splitlines(True)

        with open(filename, 'w') as fout:
            for line in fin.readlines():
                if ''.join(line.split(',')).strip() == '':
                    continue
                fout.write(line)
            x += 1            


dir_src = "in_folder"
dir_dst = "out_folder"


for file in os.listdir(dir_src):
    if x>0:
        src_file = os.path.join(dir_src, file)
        dst_file = os.path.join(dir_dst, file)
        shutil.move(src_file, dst_file)

代码现在正在执行的操作是删除文件中的所有内容并将它们移到新文件夹中。我希望我的文件是一样的，但是要删除空白行。

Answer 1

您只需将每一行输出到新文件，而无需随后进行任何移动：

dir_src = "in_folder/*.csv"
dir_dst = "out_folder"

files = glob.glob(dir_src)

# Read every file in the directory

x = 0 # counter

for filename in files:
    outfilename = os.path.join(dir_dst, os.path.basename(filename))
    with open(filename, 'r') as fin:
        with open(outfilename, 'w') as fout:
            for line in fin:
                if ''.join(line.split(',')).strip() == '':
                    continue
                fout.write(line)
            x += 1

Answer 2

尝试一下。

for filename in files:
    with open(filename, 'r') as fin:
        data = fin.read().splitlines(True)
        with open(filename, 'w') as fout:
            for line in data:
                if ''.join(line.split(',')).strip() == '':
                    continue
                fout.write(line)
            x += 1

在Python中删除csv文件中的空白行

2 个答案: