当我使用mysql进行子查询时,在“ where子句”中得到Unknown列“ tv.last_time”,该怎么办?我想在进行子查询时使用外部条件过滤掉不符合要求的记录
SELECT
info_topic.*, b.newMessage
FROM
info_topic
LEFT JOIN `info_topic_visit` AS tv ON tv.topic_id = info_topic.id
AND tv.user_id = 225
LEFT JOIN (
SELECT
p.topic_id,
count(*) AS newMessage
FROM
info_post p
WHERE
p.create_time > tv.last_time
GROUP BY
p.topic_id
) AS b ON b.topic_id = info_topic.id
ORDER BY b.newMessage DESC
数据库架构:
CREATE TABLE `info_topic` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(255) COLLATE utf8mb4_unicode_ci DEFAULT '' COMMENT 'topic name',
`summary` varchar(500) COLLATE utf8mb4_unicode_ci DEFAULT '' COMMENT 'summary`',
`create_time` datetime DEFAULT NULL COMMENT '',
`sort` int(11) DEFAULT '0' COMMENT '',
PRIMARY KEY (`id`),
);
CREATE TABLE `info_topic_visit` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`topic_id` int(11) DEFAULT '0' COMMENT '',
`user_id` int(11) DEFAULT '0' COMMENT '',
`last_time` datetime DEFAULT NULL COMMENT '',
PRIMARY KEY (`id`)
);
答案 0 :(得分:1)
子查询的问题是tv
别名在那里没有意义,因此您不能引用该别名所对应的表中的任何内容。一种方法是在select子句中将子查询转换为相关子查询:
SELECT
i.*,
(SELECT COUNT(*) FROM info_post p
WHERE p.create_time > tv.last_time AND p.topic_id = i.id) AS newMessage
FROM info_topic i
LEFT JOIN info_topic_visit AS tv
ON tv.topic_id = info_topic.id AND tv.user_id = 225
LEFT JOIN info_topic_member tm
ON i.id = tm.topic_id AND
tm.del_flag = 0 AND
tm.apply_status = i.open_type AND
tm.user_id = 225
WHERE
i.del_flag = 0 AND
i.id > 0 AND
tm.id IS NOT NULL
ORDER BY
newMessage DESC;
也许还有一种重组查询的方法,这样您就不必使用效率不高的相关子查询。