Question

Models.py 这是我的模型类，其中有2个表。每个表上都有一个称为label的字段。我的问题是我将如何比较2个标签并将值返回到新字段（returnlabel）

 class Server(models.Model):
     label = models.TextField(max_length=200,null=True)  #compare this
     upload1 = models.FileField(null=True, blank=True)
     Image1 = models.TextField(upload1, null=True)

class Android(models.Model):
     label=models.TextField(max_length=200,null=True) #with this
     imagestring=models.TextField(null=True,blank=True)
     returnlabel=models.TextField(null=True,blank=True) #return to this

序列化器类

   class FoodSerializers(serializers.HyperlinkedModelSerializer):
       class Meta:
       model=Server
       fields=('url','label','Image1','upload1')

   class AndroidSerializers(serializers.ModelSerializer):

    class Meta:
    model = Android
    fields = ('label', 'imagestring', 'returnlabel')

观看次数

 class FoodViewSet(viewsets.ModelViewSet):
    queryset = Server.objects.all()
    serializer_class =FoodSerializers

class Androids(viewsets.ModelViewSet):
   queryset =Android.objects.all()
   serializer_class = AndroidSerializers

Answer 1

您可以尝试使用SerializerMethodField。像这样尝试：

class AndroidSerializers(serializers.ModelSerializer):
    return_label =  serializers.SerializerMethodField()

    class Meta:
        model = Android
        fields = ('label', 'imagestring', 'return_label')

    def get_return_label(self, obj):
        queryset = Server.objects.filter(
            label=obj.label)
        queryset_serializer = FoodSerializers(
            queryset, many=True, read_only=True)
        return queryset_serializer.data

如何比较django 2.1中的2个字段？

1 个答案: