我具有将一些数据写入二进制文件的功能
private void writeToBinFile (List<MyClass> myObjList, string filePath)
{
FileStream fs = new FileStream(filePath, FileMode.Create);
BinaryWriter bw = new BinaryWriter(fs);
foreach (MyClass myObj in myObjList)
{
bw.Write(JsonConvert.SerializeObject(myObj));
}
bw.Close();
fs.Close();
}
我看起来像
FileStream fs = new FileStream(filePath, FileMode.Create);
BinaryReader bw = new BinaryReader(fs);
while (!filePath.EOF)
{
List<MyClass> myObjList = br.Read(myFile);
}
有人可以帮忙吗? 预先感谢
答案 0 :(得分:1)
JSON可以不带格式(没有新行)的形式保存,因此您可以在文件的每一行中保存1条记录。因此,我建议的解决方案是忽略二进制文件,而使用常规的StreamWriter:
private void WriteToFile(List<MyClass> myObjList, string filePath)
{
using (StreamWriter sw = File.CreateText(filePath))
{
foreach (MyClass myObj in myObjList)
{
sw.Write(JsonConvert.SerializeObject(myObj, Newtonsoft.Json.Formatting.None));
}
}
}
private List<MyClass> ReadFromFile(string filePath)
{
List<MyClass> myObjList = new List<MyClass>();
using (StreamReader sr = File.OpenText(filePath))
{
string line = null;
while ((line = sr.ReadLine()) != null)
{
myObjList.Add(JsonConvert.DeserializeObject<MyClass>(line));
}
}
return myObjList;
}
如果您真的想使用二进制编写器保存JSON,则可以将其更改为如下形式:
private void WriteToBinFile(List<MyClass> myObjList, string filePath)
{
using (FileStream fs = new FileStream(filePath, FileMode.Create))
using (BinaryWriter bw = new BinaryWriter(fs))
{
foreach (MyClass myObj in myObjList)
{
bw.Write(JsonConvert.SerializeObject(myObj));
}
}
}
private List<MyClass> ReadFromBinFile(string filePath)
{
List<MyClass> myObjList = new List<MyClass>();
using (FileStream fs = new FileStream(filePath, FileAccess.Read))
using (BinaryReader br = new BinaryReader(fs))
{
while (fs.Length != fs.Position) // This will throw an exception for non-seekable streams (stream.CanSeek == false), but filestreams are seekable so it's OK here
{
myObjList.Add(JsonConvert.DeserializeObject<MyClass>(br.ReadString()));
}
}
return myObjList;
}
注意:
using
,以便在释放内存时正确关闭文件Length
与Position
进行比较。