我有以下LINQ查询:
using (var context = new EUContext())
{
var tmp = context.Terms.Include(x => x.StudentCourses)
.Where(x => x.StudentID == studentId && x.DepartmentID == departmentId)
.OrderBy(x => x.AcademicYear)
.ThenBy(x=> x.TermRegistered == "Fall" ? 1 :
x.TermRegistered == "Spring" ? 2 : 3));
return tmp.ToList();
}
我正在尝试在ThenBy子句中移动OrdyBy来清理代码。我正在尝试使用如下表达式:
private static Expression<Func<string, int>> TermsOrder(string x)
{
return (x == "Fall" ? 1 :
x == "Spring" ? 2 : 3);
}
我的代码应如下所示:
using (var context = new EUContext())
{
var tmp = context.Terms.Include(x => x.StudentCourses)
.Where(x => x.StudentID == studentId && x.DepartmentID == departmentId)
.OrderBy(x => x.AcademicYear)
.ThenBy(x=> TermsOrder(x.TermRegistered));
return tmp.ToList();
}
不幸的是,该表达式不起作用,该表达式的主体中有一长条弯曲的行,并显示以下错误消息:
无法将类型'int'隐式转换为'System.Linq.Expressions.Expression>
我在做什么错?这是我第一次尝试使用表达式,但由于不完全了解表达式的工作原理,所以我缺少明显的东西。
谢谢
答案 0 :(得分:3)
这并不像看起来那么简单。您需要组合Expression
或构建Expression
来生成所需的内容,不幸的是,C#在该领域没有很多帮助。
最简单的方法是对LambdaExpression
合成使用扩展方法。它取决于某些Expression
扩展方法,以Expression
中的一个Expression
替换为另一个{1>}:
public static class ExpressionExt {
// Compose: f.Compose(g) => x => f(g(x))
/// <summary>
/// Composes two LambdaExpression into a new LambdaExpression: f.Compose(g) => x => f(g(x))
/// </summary>
/// <param name="fFn">The outer LambdaExpression.</param>
/// <param name="gFn">The inner LambdaExpression.</param>
/// <returns>LambdaExpression representing outer composed with inner</returns>
public static Expression<Func<T, TResult>> Compose<T, TIntermediate, TResult>(this Expression<Func<TIntermediate, TResult>> fFn, Expression<Func<T, TIntermediate>> gFn) =>
Expression.Lambda<Func<T, TResult>>(fFn.Body.Replace(fFn.Parameters[0], gFn.Body), gFn.Parameters[0]);
/// <summary>
/// Replaces a sub-Expression with another Expression inside an Expression
/// </summary>
/// <param name="orig">The original Expression.</param>
/// <param name="from">The from Expression.</param>
/// <param name="to">The to Expression.</param>
/// <returns>Expression with all occurrences of from replaced with to</returns>
public static Expression Replace(this Expression orig, Expression from, Expression to) => new ReplaceVisitor(from, to).Visit(orig);
}
/// <summary>
/// Standard ExpressionVisitor to replace an Expression with another in an Expression.
/// </summary>
public class ReplaceVisitor : ExpressionVisitor {
readonly Expression from;
readonly Expression to;
public ReplaceVisitor(Expression from, Expression to) {
this.from = from;
this.to = to;
}
public override Expression Visit(Expression node) => node == from ? to : base.Visit(node);
}
现在,您可以创建一个采用lambda表示要测试的字段的方法。它使用本地LambdaExpression
作为最终结果的模板:
public static class Util {
static Expression<Func<string, int>> TermOrderTemplateFn = p => (p == "Fall" ? 1 : p == "Spring" ? 2 : 3);
public static Expression<Func<TRec, int>> TermsOrder<TRec>(Expression<Func<TRec, string>> selectorFn) =>
TermOrderTemplateFn.Compose(selectorFn);
}
现在,您可以在表达式中调用方法,并传入表示所需字段(或字段表达式)的lambda进行测试:
var tmp = context.Terms.Include(x => x.StudentCourses).AsQueryable()
.Where(x => x.StudentID == studentId && x.DepartmentID == departmentId)
.OrderBy(x => x.AcademicYear)
.ThenBy(Util.TermsOrder<Term>(p => p.TermRegistered));
注意::我正在调用context.Terms.First()
Term
的类型,但是在调用TermsOrder
时需要使用实际正确的类型名称。您也可以改为使用TermsOrder((Term p) => ...)
。
我可能更愿意创建ThenBy
的特殊版本,以便您可以使用类型推断来确定记录类型:
public static class EFExt {
static Expression<Func<string, int>> TermThenOrderTemplateFn = p => (p == "Fall" ? 1 : p == "Spring" ? 2 : 3);
public static IOrderedQueryable<T> ThenByTerm<T>(this IOrderedQueryable<T> src, Expression<Func<T, string>> selectorFn) =>
src.ThenBy(TermThenOrderTemplateFn.Compose(selectorFn));
}
然后您可以直接使用它:
var tmp = context.Terms.Include(x => x.StudentCourses).AsQueryable()
.Where(x => x.StudentID == studentId && x.DepartmentID == departmentId)
.OrderBy(x => x.AcademicYear)
.ThenByTerm(p => p.TermRegistered);