我在我的ggplot上无法使用geom_smooth()时遇到问题。根据以前的帖子,我发现由于我的日期变量是字符向量,geom_smooth()无法正常工作。我正在尝试将日期从班级字符转换为班级日期,但是使用as.Date导致日期变量的类“未知”。
这是我的代码,试图修复我的班级类型:
allmovies <- allmovies %>%
clean_names() %>%
select(movie, total_box_office, theatrical_release_release_date,
running_time, mpaa, metacritic, sentiment) %>%
mutate(theatrical_release_release_date =
as.character(theatrical_release_release_date)) %>%
mutate(theatrical_release_release_date = as.Date(theatrical_release_release_date, format = "%Y-%m-%d"))
这是我的代码,用于尝试使用geom_smooth()进行绘制,以防万一有人可以帮助我在此处找到错误。
ggplotly(tooltip = c("text"),
ggplot(data = allmovies, aes(x = theatrical_release_release_date,
y = total_box_office, color = mpaa, text = movie)) +
geom_point() +
geom_smooth(method=lm) +
scale_y_continuous(labels = comma) +
labs(color = "MPAA Rating") +
ylab("Total Box Office Revenue") +
xlab("Theatrical Release Date") +
ggtitle("Total Box Office Revenue Over Time",
subtitle = "While revenue generally improved over time, a further analysis shows PG rated movies generated much more revenue over time while PG-13 and R-rated revenue correlations do not appear to be significant.")) %>%
layout(title = "Total Box Office Revenue Over Time",
font = font)
最后,这是我的日期列数据示例:
dput(head(allmovies$theatrical_release_release_date))
c("2013-08-23", "2013-03-22", "2012-09-14", "2012-03-16", "2012-02-17",
"2011-10-14")
这是整个数据的一小部分样本:
structure(list(movie = c("The Frozen Ground", "The Croods", "Stolen", "Seeking Justice", "Ghost Rider: Spirit of Vengeance", "Trespass" ), total_box_office = c(5617460, 573068425, 17967746, 411746, 149217355, 786532), theatrical_release_release_date = structure(c(15940, 15786, 15597, 15415, 15387, 15261), class = "Date"), running_time = c(105, 98, 96, 104, 95, 90), mpaa = c("R", "PG", "R", "R", "PG-13", "R"), metacritic = c(37, 55, 43, 38, 34, 37), sentiment = c(NA, 0.1363636, NA, NA, NA, NA)), row.names = c(NA, -6L), class = c("tbl_df", "tbl", "data.frame"))
答案 0 :(得分:-1)
尝试lubridate软件包:
install.packages("lubridate")
library(lubridate)
然后使用ymd函数(请按?dmy
查阅dym / ymd顺序的文档):
allmovies <- allmovies %>%
clean_names() %>%
select(movie, total_box_office, theatrical_release_release_date,
running_time, mpaa, metacritic, sentiment) %>%
mutate(theatrical_release_release_date =
as.character(theatrical_release_release_date)) %>%
mutate(theatrical_release_release_date = ymd(theatrical_release_release_date))
如果使用dput
来提供您的数据样本不起作用,我将相应地编辑答案:)。