我正在尝试在数字类型输入中为Fluke中的TextFormField添加完成按钮,但我无法做到这一点。请提供解决方案的帮助。
代码:
TextFormField(
key: Key(keyValue),
initialValue: valueBuilder,
onSaved: (text) {
fieldsController.text = text.trim();
},
inputFormatters: [inputFormatters],
keyboardType: TextInputType.phoneNumber,)
我想要创建一个this之类的键盘。对于输入文本表单字段。
答案 0 :(得分:1)
我刚刚创建了一个用于向当前键盘添加基本操作的软件包。
您可以在这里看看:
https://pub.dartlang.org/packages/keyboard_actions
用法:
import 'package:flutter/material.dart';
import 'package:keyboard_actions/keyboard_actions.dart';
//...
FocusNode _nodeText1 = FocusNode();
FocusNode _nodeText2 = FocusNode();
FocusNode _nodeText3 = FocusNode();
FocusNode _nodeText4 = FocusNode();
FocusNode _nodeText5 = FocusNode();
@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(
title: Text("Keyboard Actions Sample"),
),
body: FormKeyboardActions(
keyboardActionsPlatform: KeyboardActionsPlatform.ALL, //optional
keyboardBarColor: Colors.grey[200], //optional
nextFocus: true, //optional
actions: [
KeyboardAction(
focusNode: _nodeText1,
),
KeyboardAction(
focusNode: _nodeText2,
closeWidget: IconButton(
icon: Icon(Icons.close),
onPressed: () {},
),
),
KeyboardAction(
focusNode: _nodeText3,
onTapAction: () {
showDialog(
context: context,
builder: (context) {
return AlertDialog(
content: Text("Custom Action"),
actions: <Widget>[
FlatButton(
child: Text("OK"),
onPressed: () => Navigator.of(context).pop(),
)
],
);
});
},
),
KeyboardAction(
focusNode: _nodeText4,
displayCloseWidget: false,
),
KeyboardAction(
focusNode: _nodeText5,
closeWidget: Padding(
padding: EdgeInsets.all(5.0),
child: Text("CLOSE"),
),
),
],
child: Padding(
padding: const EdgeInsets.all(15.0),
child: SingleChildScrollView(
child: Column(
crossAxisAlignment: CrossAxisAlignment.stretch,
children: <Widget>[
TextField(
keyboardType: TextInputType.number,
focusNode: _nodeText1,
decoration: InputDecoration(
hintText: "Input Number",
),
),
TextField(
keyboardType: TextInputType.text,
focusNode: _nodeText2,
decoration: InputDecoration(
hintText: "Input Text with Custom Close Widget",
),
),
TextField(
keyboardType: TextInputType.number,
focusNode: _nodeText3,
decoration: InputDecoration(
hintText: "Input Number with Custom Action",
),
),
TextField(
keyboardType: TextInputType.text,
focusNode: _nodeText4,
decoration: InputDecoration(
hintText: "Input Text without Close Widget",
),
),
TextField(
keyboardType: TextInputType.number,
focusNode: _nodeText5,
decoration: InputDecoration(
hintText: "Input Number with Custom Close Widget",
),
),
],
),
),
),
),
);
}
答案 1 :(得分:0)
更改
keyboardType: TextInputType.number
到
keyboardType: TextInputType.numberWithOptions(signed: true, decimal: true)
答案 2 :(得分:0)
您不需要select avg(replace(salary::text, '0', '')::int) as myavg
from mytable
按钮,只需用done
包裹MaterialApp
GestureDetector
答案 3 :(得分:0)
请尝试更改为
v_message := item.notification_msg || '<br>'
答案 4 :(得分:0)
ios 键盘上没有完成按钮。解决方案是使用“keyboard_actions”插件,否则添加键盘顶部的布局检查此
https://blog.usejournal.com/keyboard-done-button-ux-in-flutter-ios-app-3b29ad46bacc
答案 5 :(得分:0)
我使用了签名选项来显示完成按钮。然后我使用 TextInputFormatter 和 RegEx 来限制用户可以输入的内容。
new TextFormField(
controller: myController,
keyboardType: TextInputType.numberWithOptions(signed:true, decimal: true),
textInputAction: TextInputAction.done,
onFieldSubmitted: (term) {
_showSnackBar(context, double.parse(myController.text));
},
onEditingComplete: () {
_showSnackBar(context, double.parse(myController.text));
},
decoration: const InputDecoration(
helperText: "Actual",
hintText: "Units used",
border: UnderlineInputBorder(),
icon: Icon(Icons.keyboard),
),
inputFormatters: <TextInputFormatter>[
FilteringTextInputFormatter.allow(RegExp(r'^\d*\.?\d*$')),
],
),
答案 6 :(得分:0)
这是在键盘打开时将完成按钮添加到您的TextFormField
的方法:
textInputAction: TextInputAction.done,
请记住,iOS 不支持在 NUMERIC
键盘上完成。
答案 7 :(得分:-1)
done
中没有iOS
按钮,但是我们可以检查输入的长度并清除focus
以隐藏数字键盘。
如下实施(将与数字值的固定长度一起使用)
onChanged: (val) {
if (val.length == 10) { //10 is the length of the phone number you're allowing
FocusScope.of(context).requestFocus(FocusNode());
}
}