Question

我正在制作discord.js机器人，我想要make命令，该命令将写入5个具有最高平衡的用户。当我运行此代码

/**
 * Instantiates an instance
 *
 * @since 6.3
 * @access public
 *
 * @param array|string $args Array or query string of arguments

 * @return object Instance object
 */
public function load_instance( $args = '' ) {
    $args['instance'] = count( $this->loaded_instances );

    $instance = new Theme_My_Login_Template( $args );

    if ( $args['instance'] == $this->request_instance ) {
        $instance->set_active();
        $instance->set_option( 'default_action', $this->request_action );
    }

    $this->loaded_instances[] = $instance;

    return $instance;
}

我得到了所有的琴弦...

let coins = require("./coins.json");
for (var key in coins) {
  if (coins.hasOwnProperty(key)) {
  console.log(key + ": " + coins[key].coins);
  }
}

因此表示：298462251453775873: 2090 208120625947082752: 210 461643208422588446: 370 290099182310785025: 10 468737161563209738: 420 381182620513468417: 40 408908116101431298: 180...。我该如何对这些值进行排序而不丢失哪个用户拥有它？

Answer 1

因此将其转换为具有Object.keys或Object.entries的数组，然后对其进行排序。

const users = {
  '1': 100,
  '2': 200,
  '3': 50
}

const sorted = Object.entries(users).sort((a, b) => a[1] > b[1] ? -1 : 1)
console.log(sorted)

const users = {
  '1': 100,
  '2': 200,
  '3': 50
}

const sorted = Object.keys(users).sort((a, b) => users[a] > users[b] ? -1 : 1)
console.log(sorted)

sorted.forEach(k => {
  console.log(k, users[k])
})

Answer 2

使用<!DOCTYPE html> <html> <head> <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <script type="text/javascript" charset="utf-8"> function doThisWhenLoaded(){ var code = document.getElementsByTagName("body"); code.append("<p>Yes it did.</p>"); } </script> </head> <body onload="doThisWhenLoaded"> <h1 style="font-family:sans-serif;">Did it work?</h1> </body> </html>和Object.keys()，可以实现所需的功能。

array.slice()

Answer 3

您可以像下面那样使用Object.entries，Array.map对对象进行排序

let coins = {
    '298462251453775873': {coins: 2090}
  , '208120625947082752': {coins: 210}
  , '461643208422588446': {coins: 370}
  , '290099182310785025': {coins: 10}
  , '468737161563209738': {coins: 420}
  , '381182620513468417': {coins: 40}
  , '408908116101431298': {coins: 180}
}

coins = Object.assign(...Object.entries(coins)
                               .sort(([,a],[,b]) => a.coins - b.coins)
                               .map(([k,v]) => ({[k]: v})))

for (var key in coins) {
  if (coins.hasOwnProperty(key)) {
  console.log(key + ": " + coins[key].coins);
  }
}

//console.log(coins)

如何按key.coins值对数组中的对象排序？从JSON

3 个答案: