Question

我能够输出最高的值，但是当我执行.getNames时却无法正常工作，因为它显示了一个错误

错误是我似乎无法显示关联名称的最高值，而只显示余额

    //Highest Balance
    Double largest = customer[0].getBalance();

    for (int i=0; i<customer.length; i++)
    {
        if(customer[i].getBalance() > largest) 
            largest = customer[i].getBalance(); 

    }
    System.out.println("The highest balance is " + largest);

Answer 1

我想在您的课程中必须有一个方法getName()或类似的方法，例如getBalance()方法：

Double largest = customer[0].getBalance();
String name = customer[0].getName();
for (int i = 1; i < customer.length; i++) {
    if(customer[i].getBalance() > largest) { 
        largest = customer[i].getBalance(); 
        name =  = customer[i].getName(); 
    }
}
System.out.println("The highest balance is " + largest);
System.out.println("The customer with highest balance is " + name);

由于您已经将第一项（位置= 0）的值分配给了largest和name，因此您也可以从第二个数组项（位置= 1）开始循环。

Answer 2

这可能会有所帮助：

    Double largest = customer[0].getBalance();
    String nameOfCustomer = "";
    for (int i = 0; i < customer.length; i++) {
        if (customer[i].getBalance() > largest) {
            largest = customer[i].getBalance();
            nameOfCustomer = customer[i].getName();
        }
    }
    System.out.println("The highest balance is " + largest + 
                        " for customer " + nameOfCustomer);

这里使用的逻辑与您找到最高余额的逻辑相同。

Answer 3

您还需要存储与最大值关联的名称。您可以在更新largest余额时更新它，也可以存储拥有最大值（和最大余额）的整个customer对象。示例：

Double largest = customer[0].getBalance();
String name = "";

for (int i=0; i<customer.length; i++)
{
     if(customer[i].getBalance() > largest) 
     {
            largest = customer[i].getBalance();
            name = customer[i].getName();
      }
 }
 System.out.println("The highest balance is " + largest);
 System.out.println("The name of the customer is " + name);

程序显示最高值，但不显示最高值的人

3 个答案: