Question

你好，我遇到这样的情况：

(
    {
        "Nov 2018" =         {
            AudioFileURL = "https://www.GeorgeA.m4a";
            AudioFileText = "GeorgeA";
        };
    },

    {
        "Nov 2018" =         {
            AudioFileURL = "https://www.GeorgeB.m4a";
            AudioFileText = "Georgeb";
        };
    },
    {
        "Nov 2018" =         {
            AudioFileURL = "https://www.Georgec.m4a";
            AudioFileText = "Georgec";
        };
    },
    {
        "Sep 2018" =         {
            AudioFileURL = "https://www.GeorgeB.m4a";
            AudioFileText = "GeorgeD";


        };
    }
)

现在，我想将所有Values与同一个键组合在一起，以便可以在带有UITableView controller的部分中使用它们。有人可以为我提供一些指导吗。

我正在寻找的输出是这样的

(
{
        "Nov 2018" = {        
            [AudioFileURL = "https://www.GeorgeA.m4a";
            AudioFileText = "GeorgeA"],

            [AudioFileURL = "https://www.GeorgeB.m4a";
            AudioFileText = "GeorgeB"],

            [AudioFileURL = "https://www.GeorgeC.m4a";
            AudioFileText = "GeorgeC"];

        };
    },
{
        "Sep 2018" =         {
            [AudioFileURL = "https://www.GeorgeB.m4a";
            AudioFileText = "GeorgeD";]


        };
}
)

Answer 1

首先在一个单元格中构建一个表示所需信息的结构：

struct AudioFileInfo {
    let urlString: String
    let text: String

    init(dict: [String: String]) {
        urlString = dict["AudioFileURL"] ?? ""
        text = dict["AudioFileText"] ?? ""
    }
}

struct CellInfo {
    let date: String
    let audioFileInfos: [AudioFileInfo]
}

然后您可以：

let cellInfos = response
    .flatMap {
        $0.map { ($0.key, AudioFileInfo(dict: $0.value)) }
    }
    .reduce([CellInfo]()) { partial, item in
        var new = partial
        if let index = partial.index(where: { $0.date == item.0 }) {
            new[index] = CellInfo(date: partial[index].date, audioFileInfos: partial[index].audioFileInfos + [item.1])
        }
        else {
            new.append(CellInfo(date: item.0, audioFileInfos: [item.1]))
        }
        return new
    }

这将为您提供CellInfo对象的数组。

通常，这是解决此类问题的方式。首先定义一个代表所需输出的类型，然后操纵输入，直到创建该类型的对象。游乐场是您做这种事情的朋友。

Answer 2

类似的事情将为您服务

typealias AudioFile = (url: String, text: String)

class DictArray {
    var items: [MainModal]

    class MainModal {
        let date: String
        var files: [AudioFile]

        init(key: String, file: AudioFile) {
            self.key = key
            self.files = [file]
        }

    }

    init(dictArray: [[String: [String: String]]]) {
        for dict in dictArray {
            if let date = dict.keys.first {
                if let item = items.first(where: { $0.date == date }) {
                    guard let value = dict.values.first as? [String: String] else { continue }
                    let file = AudioFile(url: value["AudioFileURL"]!, text: value["AudioFileText"]!)
                    item.files.append(file)
                } else {
                    guard let value = dict.values.first as? [String: String] else { continue }
                    let file = AudioFile(url: value["AudioFileURL"]!, text: value["AudioFileText"]!)
                    items.append(MainModal(key: date, files: [file]))
                }
            }
        }
    }
}

DictArray(dict: json)

如何将值与NSdictionary的相似键合并

2 个答案: