Question

我有一个问题，就是将数据插入到oracle数据库的表EMPLOYEES中。已经有一段时间了，我现在无法弄清楚我的代码出了什么问题。

这是我的html页面代码：employeeHire.php

<div class="container col-lg-6 col-md-10 mb-8 " >
    <form action="employeHirePost.php" method="POST">
        <p class="h4 text-center mb-4">Enregistrez un nouvel employé dans l'entreprise</p>

        <label for="defaultFormLoginEmailEx" class="grey-text ">Entrez l'ID de L'employé</label>
        <input type="text" id="defaultFormLoginEmailEx" name="id" class="form-control ">
        <br/>
        <label for="defaultFormLoginPasswordEx" class="grey-text">Son Job ID</label>
        <input type="text" id="defaultFormLoginPasswordEx"  name="job"class="form-control">
        <!--<select type="text" name="job" id="defaultFormLoginEmailEx" class="form-control ">
            <option>Sélectionnez Job Id...</option>
<?php
    $connection = new PDO("oci:dbname=localhost/XE", "hr", "123"); 
    $reponse = $connection->query('SELECT job_id FROM jobs');
    while ($donnees=$reponse->fetch()) {
        echo "<option> $donnees[JOB_ID] </option>";
    }
?>
        </select>-->
         <br/>
        <label for="defaultFormLoginPasswordEx" class="grey-text">Son Nom</label>
        <input type="text" id="defaultFormLoginPasswordEx" name="first_name" class="form-control">
         <br/>
        <label for="defaultFormLoginPasswordEx" class="grey-text">Son Prénom</label>
        <input type="text" id="defaultFormLoginPasswordEx"  name="last_name"class="form-control">
         <br/>
        <label for="defaultFormLoginPasswordEx" class="grey-text">Son Email</label>
        <input type="text" id="defaultFormLoginPasswordEx"  name="email"class="form-control">
        <br/>
        <label for="defaultFormLoginPasswordEx" class="grey-text">Son Numéro de Téléphone</label>
        <input type="number" id="defaultFormLoginPasswordEx"  name="phone"class="form-control">
        <br/>
        <label for="defaultFormLoginPasswordEx" class="grey-text">Salaire</label>
        <input type="number" id="defaultFormLoginPasswordEx"  name="salaire"class="form-control">
        <br/>
        <label for="defaultFormLoginPasswordEx" class="grey-text">Date D'embauche</label>
        <input type="date" id="defaultFormLoginPasswordEx"  name="hire_date"class="form-control">
        <label for="defaultFormLoginPasswordEx" class="grey-text">Commission</label>
        <input type="number" id="defaultFormLoginPasswordEx"  name="com"class="form-control">
        <br/>
        <label for="defaultFormLoginPasswordEx" class="grey-text">Manager id</label>
        <input type="number" id="defaultFormLoginPasswordEx"  name="man"class="form-control">
        <br/>
        <label for="defaultFormLoginPasswordEx" class="grey-text">Departement id</label>
        <input type="number" id="defaultFormLoginPasswordEx"  name="dep"class="form-control">
        <br/>
        <div class="text-center mt-4">
            <button class="btn btn-indigo" class="waves-light" mdbTooltip="Cliquez pour enregistrer le nouvel employé" placement="top" mdbWavesEffect type="submit">Enregistrer Le Nouvel Employé</button>
        </div>
    </form>
</div>

这是ACTION页面，负责插入到DB :: employeeHirePost.php

<?php
    include("connexion.php");

    /*$date=date("d/m/y",strtotime($_POST['hire_date']));*/

    if( isset($_POST['job']) ) {
        $connection->beginTransaction();
        $date = date('d/m/y', strtotime($_POST['hire_date']));

        $request = $connection->prepare('INSERT INTO EMPLOYEES
                            (EMPLOYEE_ID,JOB_ID,FIRST_NAME,LAST_NAME,
                            EMAIL,PHONE_NUMBER,HIRE_DATE,SALARY,
                            COMMISSION_PCT,MANAGER_ID,DEPARTMENT_ID) 
                    VALUES(?,?,?,?,?,?,?,?,?,?,?)');

        $request->execute(array(intval($_POST['id']),$_POST['job'],
                            $_POST['first_name'],$_POST['last_name'],$_POST['email'],
                            $_POST['phone'],$date,intval($_POST['salaire']),
                            intval($_POST['com']),intval($_POST['man']),
                            intval($_POST['dep'])));

        $connection->commit();
    }

    header('Location: employeHire.php');
?>

当我执行代码时就没有问题，就是它不会插入任何数据。拥有Oracle XE 11g的人可以尝试使用它。

Answer 1

Bonjour ！！！！政法事务总书记处处长。政变甲骨文负责人甲骨文负责人与警察联系。

将数据插入到DATABASE ORACLE的表EMPLOYEE中

1 个答案: