WinDbg和SoS,我如何打印/转储大字符串?

时间:2011-03-18 09:09:12

标签: .net debugging windbg dump sos

我正在使用带有SoS扩展名的WinDbg调试来自生产服务器的hangdump。

其中一个堆栈中有一个字符串参数,我需要知道它的值。但是,它是一个相当大的字符串,当我使用DumpObj时,WinDbg将不会打印它。这是DumpObj

的输出
0:036> !do 00000001b30d8668
Name: System.String
MethodTable: 0000064278436728
EEClass: 000006427803e520
Size: 5125300(0x4e34b4) bytes
 (C:\WINDOWS\assembly\GAC_64\mscorlib\2.0.0.0__b77a5c561934e089\mscorlib.dll)
String: <String is invalid or too large to print>

Fields:
              MT    Field   Offset                 Type VT     Attr            Value Name
000006427843d998  4000096        8         System.Int32  1 instance          2562638 m_arrayLength
000006427843d998  4000097        c         System.Int32  1 instance          2562637 m_stringLength
0000064278438170  4000098       10          System.Char  1 instance               3c m_firstChar
0000064278436728  4000099       20        System.String  0   shared           static Empty
                                 >> Domain:Value  0000000000163260:000000007fff0370 00000000001a6760:000000007fff0370 <<
0000064278438020  400009a       28        System.Char[]  0   shared           static WhitespaceChars
                                 >> Domain:Value  0000000000163260:000000007fff0b60 00000000001a6760:000000007fff89f0 <<

如何获取此字符串实例的值?最好转储到文件中。

4 个答案:

答案 0 :(得分:13)

这是我写的一个脚本,用于将字符串转储到windbg中的文件。

$$ Dumps the managed strings to a file
$$ Platform x86
$$ Usage $$>a<"c:\temp\dumpstringtofolder.txt" 6544f9ac 5000 c:\temp\stringtest
$$ First argument is the string method table pointer
$$ Second argument is the Min size of the string that needs to be used filter
$$ the strings
$$ Third is the path of the file
.foreach ($string {!dumpheap -short -mt ${$arg1}  -min ${$arg2}})
{ 

  $$ MT        Field      Offset               Type  VT     Attr    Value Name
  $$ 65452978  40000ed        4         System.Int32  1 instance    71117 m_stringLength
  $$ 65451dc8  40000ee        8          System.Char  1 instance       3c m_firstChar
  $$ 6544f9ac  40000ef        8        System.String  0   shared   static Empty

  $$ start of string is stored in the 8th offset, which can be inferred from above
  $$ Size of the string which is stored in the 4th offset
  r@$t0=  poi(${$string}+4)*2
  .writemem ${$arg3}${$string}.txt ${$string}+8 ${$string}+8+@$t0
}

这就是它的使用方法$$>a<”c:\temp\dumpstringtofolder.txt” 6544f9ac 5000 c:\temp\stringtest

转储的内容将采用Unicode格式,要查看其内容,请使用以下内容Console.WriteLine(ASCIIEncoding.Unicode.GetString(File.ReadAllBytes(@"c:\temp\stringtest03575270.txt")));

HTH

答案 1 :(得分:7)

在转储2562638个字符的文本之前我会三思而行,但是如果你真的想要,那么文本会存储在字符串实例的字段之后,所以你可以做一个du <address+offset> <end address>转储实际的文本字符串。输出看起来像这样:

00000000`132ab050  "this is an extremely long string"
00000000`132ab090  " of text, so don't even bother t"
00000000`132ab0d0  "o try to dump it to the screen -"

通过将会话输出记录到文件中,您可以轻松捕获输出并执行所需的任何后处理。

答案 2 :(得分:1)

如果您赶时间,请在WinDbg中启用日志后运行!do。在日志文件中,您将获得整个字符串。

在WinDbg菜单中,转到编辑 - &gt;打开/关闭日志文件,设置日志文件路径。

答案 3 :(得分:1)

我已修改@Naveen的脚本以在x64平台上工作。

很棒的脚本!

$$ Dumps the managed strings to a file
$$ Platform x64
$$ Usage $$>a<"c:\temp\dumpstringtofolder.txt" 00007ffa6c509808 5000 c:\temp\stringtest
$$ First argument is the string method table pointer
$$ Second argument is the Min size of the string that needs to be used filter
$$ the strings
$$ Third is the path of the file
.foreach ($string {!dumpheap -short -mt ${$arg1}  -min ${$arg2}})
{ 
    $$               MT    Field   Offset                 Type VT     Attr            Value Name
    $$ 00007ffa6c50c158  400027b        8         System.Int32  1 instance               18 m_stringLength
    $$ 00007ffa6c50a9c0  400027c        c          System.Char  1 instance               53 m_firstChar
    $$ 00007ffa6c509808  4000280       c0        System.String  0   shared           static Empty

    $$ start of string is stored in the 8th offset, which can be inferred from above
    $$ Size of the string which is stored in the c-th offset
    r@$t0= (poi(${$string}+8) & 00000000FFFFFFFF) *2
    .writemem ${$arg3}${$string}.txt (${$string}+c) (${$string}+c+@$t0)
}