Question

我正在做一个学校项目。

该项目的意思是我创建了一个login/registration form，

我可以在其中注册，登录和查看记录。

但是我还需要创建一个下拉菜单，以便我可以看到所有记录（用户），并且在其下方我需要创建一个按钮，当我选择一个记录/用户并按下Delete按钮时，需要从中删除数据库。而且我不知道该怎么做。

这是我的代码：

<?php

include（“ connectie.php”）; 包括（“ deletecode.php”）;

$conn = new mysqli("localhost", "student14_admin", "lol12345","student14_jordi");
mysqli_select_db($conn,'student14_jordi');

$sql = "DELETE FROM users WHERE ID='$_GET[id]'";



echo "<select name='user'>";
    if ($result->num_rows>0) {
    while($row = $result->fetch_assoc()) {
        echo "<option value=" . $row['username'] . ">" . $row['username'] . "</option>";
    }
    }
    echo "</select>";

?>


<form action="">
<a class="delete" href="delete.php?id=<?php echo $row['id']; ?>">Delete</a>
</form>

Answer 1

创建一个按钮并将其命名为删除

<a class="delete" href="delete.php?id=<?php echo $row['id']; ?>">Delete</a>

然后创建一个delete.php文件，并在其中保存这些代码。

<?php include_once 'db_config_filename.php';
 // get id value
 $id = $_GET['id'];

// sql to delete a record
$sql = "DELETE FROM tablename WHERE id='$id'";

// print_r($sql);

if (mysqli_query($conn, $sql)) {
   echo "Record deleted successfully";
} 
else {
    echo "Error deleting record: " . mysqli_error($conn);
}

 //redirect here
include 'data.php';

?>

Answer 2

我几乎可以正常工作了。我现在有了这段代码：

delete.php:

<?php

include ("connectie.php");


$sql = "SELECT * FROM users ";
$result = $conn->query($sql);

echo "<select name='user'>";
    if ($result->num_rows>0) {
    while($row = $result->fetch_assoc()) {
        echo "<option value=" . $row['username'] . ">" . $row['username'] . " 
</option>";
    }
    }
    echo "</select>";

?>


<form action="" method="GET">
<input type="hidden" name="id" value=".$row['id']." />
<input type="submit" name="delete" value="verwijderen">
</form>

<?php
    include ("deletecode.php");
?>

Deletecode.php:

<?php
$servername = "localhost";
$username = "student14_admin";
$password = "lol12345";
$dbname = "student14_jordi";

// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}

// sql to delete a record
$sql = "DELETE FROM users WHERE id=3";

if (mysqli_query($conn, $sql)) {
echo "Record deleted successfully";
} else {
echo "Error deleting record: " . mysqli_error($conn);
}

mysqli_close($conn);
?>

这仅适用于记录3次事件。但是现在我需要确保，如果我从下拉菜单中选择一条记录，然后单击删除按钮，它需要从我的数据库中删除该记录。

尝试创建删除按钮以删除数据库中的记录

2 个答案: