Question

此处的完整代码：https://drive.google.com/open?id=1iCfj5fLjuD42LLkfhuZoT_7gmXZgHUdk

我正在制作游戏，当我被困在需要从房间中取出物品时将其从房间中取出的时候。

您将键入->，然后选择您要在该房间中拿起的物品。

因此，例如->选择然后->摇滚。

我想要做的是将'rock'添加到库存中，并且仅从播放器当前所在的房间（maplocation[myPlayer.location][EXAMINATION]）的EXAMINATION键中删除该字符串。

inventory = ['sword', 'map', 'bread', 'enchanted rod', 'water' ]

maplocation = {
'Mountains': {
    ZONENAME: 'Mountains',
    EXAMINATION: "rock, twig, snow",
    SIDE_UP: '',
    SIDE_DOWN: 'Vallee',
    SIDE_LEFT: '',
    SIDE_RIGHT: 'Start',
},
}

def inventory_pick(myAction):
    print('What do you want to pick up?')
    pickup = input('-> ')
    current_room = maplocation[myPlayer.location]
    if current_room.get(EXAMINATION, None) == pickup:
        inventory.append(pickup)
        del current_room[EXAMINATION, pickup]
        print(pickup + " has been added to your inventory")
    else:
        print("There is no " + pickup + " here!" )

Answer 1

您的代码虽然不太合理。我猜想，如果玩家的pickup与当前房间的“检查”相同，您想从当前房间中删除“检查”吗？

所以不是

if pickup in maplocation[myPlayer.location][EXAMINATION]:
    inventory.append(pickup)
    print(pickup + " has been added to your inventory")
    for EXAMINATION in maplocation[myPlayer.location][EXAMINATION].value():
        del EXAMINATION[pickup]

您应该

current_room = map_locations[my_player.location]  # break it up to give 
                                                  # semantic meaning to your code
if current_room.get(EXAMINATION, None) == pickup:
    inventory.append(pickup)
    del current_room[EXAMINATION]
    # or current_room.pop(EXAMINATION, None)

Answer 2

我不认为您正在尝试调用EXAMINATION，因为它只是一个字符串。这就是我根据您提供的代码可以想到的：

def inventory_pick(myAction):
    print('What do you want to pick up?')
    pickup = input('-> ')
    if pickup in maplocation[myPlayer.location][EXAMINATION]:
        inventory.append(pickup)
        print(pickup + " has been added to your inventory")
        del maplocation[myPlayer.location][EXAMINATION][pickup]
    else:
        print("There is no " + pickup + " here!" )

删除嵌套字典中的字符串

2 个答案: