Question

我是Java的初学者，我需要日程帮助，我想打印字符串的最后一个字符，然后打印最后两个。.依此类推。

非常感谢您的时间和帮助。（我不需要视频教程建议等。）

String vacantion = "Vacantion";

int number = 1;

for (int i = 0; i < vacantion.length(); i++) 
{
    System.out.println(vacantion.charAt(vacantion.length() - number));

    number++;
}

// The output should look like this //
// n,
// on,
// ion,
// tion,

// so on.

Answer 1

您需要用子字符串方法替换charAt方法：

String vacantion = "Vacantion";

int number = 1;

for (int i = 0; i < vacantion.length(); i++)
{
    System.out.println(vacantion.substring(vacantion.length() - number));

    number++;
}

Answer 2

要获取任何字符串的字符，可以使用String.substring（firstIndex，lastIndex）或String.charAt（index）。

String.substring（firstIndex，lastIndex）将为您提供firstIndex和lastIndex之间的字母（包括first，不包括last），而charAt（index）将为您返回String中该索引处的char（请注意，charAt（）将始终且仅返回1个字符）。

例如：

Assembly reference changes detected. Restarting host...
Environment shutdown has been triggered. Stopping host and signaling shutdown.
completed successfully
Function completed (Success, Id=d5042f25-18d9-489a-81fe-05ae07607012, Duration=10921ms)
Executed 'AzureBillFunc' (Succeeded, Id=d5042f25-18d9-489a-81fe-05ae07607012)
The host started (12276ms)
A ScriptHost error has occurred
Microsoft.Azure.WebJobs.Host: Cannot access a disposed of object. Stopping Host

希望这会有所帮助！

如何获得字符串的最后一个字符，然后是最后两个，依此类推？

2 个答案: