Question

我需要用户输入三个数字，并且我的程序必须显示这些数字中的最大数字。我似乎无法找出问题所在。我得到的结果是 “最大数量是0.000”

#include <stdio.h>

int main()
{

double n1, n2, n3;

printf("Enter your three numbers: ");
scanf("%1f %1f, %1f", &n1, &n2, &n3);

if (n1>= n2 && n1>= n3)
    printf("The greatest number is %f", n1);

if (n2>=n1 && n2>= n3)
    printf("The greatest number is %f", n2);

if (n3>=n2 && n3>=n1)
    printf("The greatest number is %f", n3);


return 0;
}

Answer 1

编译器知道！

$ gcc -Wall temp.c
temp.c:9:23: warning: format specifies type 'float *' but the argument has type 'double *' [-Wformat]
scanf("%1f %1f, %1f", &n1, &n2, &n3);
       ~~~            ^~~
       %1lf
temp.c:9:28: warning: format specifies type 'float *' but the argument has type 'double *' [-Wformat]
scanf("%1f %1f, %1f", &n1, &n2, &n3);
           ~~~             ^~~
           %1lf
temp.c:9:33: warning: format specifies type 'float *' but the argument has type 'double *' [-Wformat]
scanf("%1f %1f, %1f", &n1, &n2, &n3);
                ~~~             ^~~
                %1lf
3 warnings generated.

Answer 2

正如Vorsprung所述，您需要一种正确的格式来读取/显示，所以：

#include <stdio.h>

int main()
{

    double n1, n2, n3;

    printf("Enter your three numbers: ");
    scanf("%lf %lf, %lf", &n1, &n2, &n3);

    if (n1>= n2 && n1>= n3)
            printf("The greatest number is %lf", n1);

    if (n2>=n1 && n2>= n3)
            printf("The greatest number is %lf", n2);

    if (n3>=n2 && n3>=n1)
            printf("The greatest number is %lf", n3);


    return 0;
}

查找最大的数字（C）-代码不起作用

2 个答案: