TornadoFX指南:如何实现客户类

时间:2018-11-26 10:32:39

标签: kotlin tornadofx

我从这里开始遵循TornadoFX指南,试图运行示例向导: Wizard

并实现了以下附加类Customer,该类未运行:

package com.example.demo.app

import javafx.beans.property.SimpleIntegerProperty
import javafx.beans.property.SimpleObjectProperty
import javafx.beans.property.SimpleStringProperty
import java.time.LocalDate
import java.time.Period
import tornadofx.*

class Customer(name: String, zip: Int, city: String, type: String) {
    val zipProperty = SimpleIntegerProperty(zip)
    var zip by zipProperty

    val nameProperty = SimpleStringProperty(name)
    var name by nameProperty

    val cityProperty = SimpleStringProperty(city)
    var city by cityProperty

    val typeProperty = SimpleStringProperty(type)
    var type by typeProperty

}

如何添加此处引用的Customer.Type,这些类摘自《指南》:

package com.example.demo.view

import com.example.demo.app.Customer
import com.example.demo.app.CustomerModel
import tornadofx.*
class CustomerWizard : Wizard() {
    val customer: CustomerModel by inject()

    override val canGoNext = currentPageComplete
    override val canFinish = allPagesComplete

    init {
        add(BasicData::class)
        add(AddressInput::class)
    }
}

class BasicData : View("Basic Data") {
    val customer: CustomerModel by inject()

    override val complete = customer.valid(customer.name)

    override val root = form {
        fieldset(title) {
            field("Type") {
                combobox(customer.type, Customer.Type.values().toList()) //Customer.Type, what is it?
            }
            field("Name") {
                textfield(customer.name).required()
            }
        }
    }
}

class AddressInput : View("Address") {
    val customer: CustomerModel by inject()

    override val complete = customer.valid(customer.zip, customer.city)

    override val root = form {
        fieldset(title) {
            field("Zip/City") {
                textfield(customer.zip) {
                    prefColumnCount = 5
                    required()
                }
                textfield(customer.city).required()
            }
        }
    }
}

错误如下,让我想知道什么是Type?枚举,类,...? Error:(26, 50) Kotlin: Unresolved reference: Type

1 个答案:

答案 0 :(得分:1)

在上面的示例中,Type是在Customer类内部定义的枚举,例如:

class Customer(name: String, zip: Int, city: String, type: Customer.Type) {
    enum class Type {
        Private, Company
    }

    val zipProperty = SimpleIntegerProperty(zip)
    var zip by zipProperty

    val nameProperty = SimpleStringProperty(name)
    var name by nameProperty

    val cityProperty = SimpleStringProperty(city)
    var city by cityProperty

    val typeProperty = SimpleObjectProperty<Type>(type)
    var type by typeProperty

}

请注意,typeProperty也更改为SimpleObjectProperty<Type>