Question

所以我需要一些帮助。我有一个服务器日志，需要从日志中过滤出错误代码（404）。到目前为止，我已经从日志中删除了错误代码，但仍然显示了我不需要的成功连接代码（200）。我是C＃的新手，所以需要任何帮助。

这就是我所拥有的：

private void btnOpen_Click(object sender, EventArgs e)
{
    openFileDialog1.ShowDialog();
    string filename = openFileDialog1.FileName;            
    StreamReader streamreader = new StreamReader(filename);
    string value = filename;
    while (!streamreader.EndOfStream)
    {
        string data = bestand.ReadLine();   
        // Split the data to keep only the error codes
        string[] errorcodeArray = data.Split('"');
        string trim = Regex.Replace(errorcodeArray[2], @"", "");
        // Trim to keep only the 3 figure codes
        trim = trim.Substring(0, trim.IndexOf(" ") + 5);
        txtLog.Text += Environment.NewLine + data;
        txtError.Text += Environment.NewLine + trim;
        // Couldn't get the 404's out of this.
    }
    streamreader.Close();

日志样本：

109.169.248.247 - - [12/Dec/2015:18:25:11 +0100] "GET /administrator/ HTTP/1.1" 200 4263 "-" "Mozilla/5.0 (Windows NT 6.0; rv:34.0) Gecko/20100101 Firefox/34.0" "-" 
109.169.248.247 - - [12/Dec/2015:18:25:11 +0100] "POST /administrator/index.php HTTP/1.1" 200 4494 "almhuette-raith.at/administrator" "Mozilla/5.0 (Windows NT 6.0; rv:34.0) Gecko/20100101 Firefox/34.0" "-" 
46.72.177.4     - - [12/Dec/2015:18:31:08 +0100] "GET /administrator/ HTTP/1.1" 200 4263 "-" "Mozilla/5.0 (Windows NT 6.0; rv:34.0) Gecko/20100101 Firefox/34.0" "-"

Answer 1

单线：

var lines = File.ReadAllLines(/*path*/);
var result = lines.Select(x=> Regex.Replace(x, @"HTTP/1.1"" \d+ ", @"HTTP/1.1"" "));

它将过滤所有代码。仅需200和404：

var result = lines.Select(x=> Regex.Replace(x, @"HTTP/1.1"" (200|404) ", @"HTTP/1.1"" "));

Answer 2

我相信您只需要“ 404”代码，并且在示例中不显示任何这些代码。如果它们是相同的格式，则应该起作用：

openFileDialog1.ShowDialog();
string filename = openFileDialog1.FileName;
var rows = File.ReadAllLines(filename);
var results = rows.Where(r => r.Split('"')[2].Trim().StartsWith("404"));

如果日志文件很大，并且您不想一次全部读取它，则应该在循环中进行测试。这是一个如何循环执行的完整示例：

openFileDialog1.ShowDialog();
string filename = openFileDialog1.FileName;
string data;
//using a string builder to concat strings is much more efficient
StringBuilder sbLog = new StringBuilder();
StringBuilder sbError = new StringBuilder();

using (StreamReader file = new StreamReader(filename))
{
   while ((data = file.ReadLine()) != null)
   {
      if (data.Split('"')[2].Trim().StartsWith("404"))
      {
         sbLog.Append(data + Environment.NewLine);
         sbError.Append(data.Split('"')[2].Trim().Substring(0, 3) + Environment.NewLine);
      }
   }                
}

txtLog.Text = sbLog.ToString();
txtError.Text += sbError.ToString();

仅解析特定文本/整数

2 个答案: