Question

JavaScript有一个奇怪的问题。我在textbox'25000000'中有文字值使用parsefloat(txt.value)，返回值为25000！??

为什么将25000000更改为25000？

Answer 1

我认为您的数字中某处有一个字母。检查下面的示例。您的代码中有错误。

parseFloat(" 250000000 ") = 250000000
parseFloat("2018@geeksforgeeks") = 2018
parseFloat("geeksforgeeks@2018") = NaN

Answer 2

感谢所有回复。问题出在价格上。当然我们用''替换'，'，但是替换方法仅更改第一个，如“ 25,000,000,000” =>“ 25000,000,000”。我使用了#include<bits/stdc++.h> using namespace std; bool recursion(int pos, int n, int sum, vector<int>&sequence,int &baseSum, vector< vector<int> >&dp) { if (pos == n) { if (sum == baseSum) return true; else return false; } if (dp[pos][sum] != -1) return dp[pos][sum]; bool resultTakingPositive = recursion(pos + 1, n, sum + sequence[pos], sequence, baseSum, dp); bool resultTakingNegative = recursion(pos + 1, n, sum - sequence[pos], sequence, baseSum, dp); dp[pos][sum] = (resultTakingPositive || resultTakingNegative); return dp[pos][sum]; } void printSolution(int pos, int n, int sum, vector<int>&sequence,int &baseSum, vector< vector<int> >&dp) { if (pos == n) { cout<<endl; return; } bool resultTakingPositive = recursion(pos + 1, n, sum + sequence[pos], sequence, baseSum, dp); if (resultTakingPositive == true) { cout<< "+ "; printSolution(pos + 1, n, sum + sequence[pos], sequence, baseSum, dp); } else { cout<< "- "; printSolution(pos + 1, n, sum - sequence[pos], sequence, baseSum, dp); } } int main() { vector<int>sequence; int n, baseSum = 0; scanf("%d",&n); for (int i = 1; i <= n; i++) { int x; scanf("%d",&x); sequence.push_back(x); baseSum += x; } vector< vector<int> >dp(n, vector<int>(2*baseSum + 1, -1)); if (recursion(0, n, baseSum, sequence, baseSum, dp)) { // if possible to make sum 0 then printSolution(0, n, baseSum, sequence, baseSum, dp); } return 0; }，问题解决了，parsefloat正确返回了。问候阿里

JavaScript parseFloat（）更改编号

2 个答案: