所以我有三个文件:Pellets.c
,Fish.c
和SwimMill.c
。 SwimMill称丸和鱼,应该分叉。但是,当我尝试分叉药丸时,出现错误消息“药丸分叉失败:错误的地址”。有人知道是什么问题吗?
include.h
#include <stdio.h>
#include <sys/ipc.h>
#include <sys/shm.h>
#include <unistd.h>
#include <stdlib.h>
#include <signal.h>
#define SHM_SIZE 1000
int shmid;
int *shm;
pid_t fish;
pid_t pellet;
void attachSharedMemory() {
key_t key = ftok("SwimMill.c", 'b'); //generate random key
shmid = shmget(key, SHM_SIZE, IPC_CREAT|0666);
shm = shmat(shmid, NULL, 0);
}
SwimMill.c
// Uses both fish and pellets, 30 seconds, then print it out
// Create pellets at random intervals, from 0x80
// Eating --> Get rid of most significant bit
// Use shared memory for fish and pellet position only
#include <stdio.h>
#include <sys/ipc.h>
#include <sys/shm.h>
#include <sys/types.h>
#include <signal.h>
#include <stdlib.h>
#include <time.h>
#include <unistd.h>
#include "include.h"
#define SHM_SIZE 1000
void printGrid(int*);
void handler(int);
void killProgram(pid_t, pid_t, int*, int);
pid_t fish;
pid_t pellet;
int main(int argc, char* argv[]) {
int timer = 0;
attachSharedMemory(); // from include.h
signal(SIGINT, handler);
// Initializing the shared memory to prevent segmentation fault
// for (int i = 0; i < SHM_SIZE; i++){
// shm[i] = -1;
// }
srand(time(NULL));
fish = fork();
if (fish == -1) {
perror("Fish fork failed1");
exit(1);
} else if (fish == 0) {
execv("Fish", argv);
perror("Fish exec failed");
exit(1);
}
while(timer <= 30){
pellet = fork();
if (pellet == -1) {
perror("Pellet Fork failed1");
exit(1);
} else if (pellet == 0) {
execv("Pellets", argv);
perror("Pellets Fork failed");
exit(1);
}
printGrid(shm);
sleep(1);
printf("Timer: %d\n", timer);
timer++;
}
killProgram(fish, pellet, shm, shmid);
getchar(); // Pause consol
return 0;
}
void printGrid(int* shm) {
int row = 10;
int column = 10;
char (*stream)[row][column]; //2D Dimensional array, fish can only move last row of 2d
//Initializing grid first
for (int i = 0; i < row; i++) {
for (int j = 0; j < column; j++) {
(*stream)[i][j] = '~';
}
}
printf("Fish: %d \n", shm[0]);
printf("Shm2 is: %d \n", shm[1] );
for (int k = 1; k < 20; k++) {
(*stream)[shm[k]/10][shm[k]%10] = 'O'; // pellets
}
(*stream)[shm[0]/10][shm[0]%10] = 'Y'; // Fish
for (int i = 0; i < row; i++) {
for (int j = 0; j < column; j++) {
printf("%c ", (*stream)[i][j]);
}
printf("\n");
}
}
void killProgram(pid_t fish, pid_t pellet, int *shm, int shmid) {
kill(fish,SIGUSR1);
kill(pellet, SIGUSR1);
sleep(5);
shmdt(shm);
shmctl(shmid, IPC_RMID, NULL);
printf("Program finished! \n");
}
void handler(int num ) {
kill(fish,SIGUSR1);
kill(pellet, SIGUSR1);
shmdt(shm);
shmctl(shmid, IPC_RMID, NULL);
perror(" Interrupt signal is pressed!! \n");
exit(1);
}
Pellets.c
// Multiple pellets
//Process ID, position, eaten/misse
#include <stdio.h>
#include <sys/ipc.h>
#include <sys/shm.h>
#include <unistd.h>
#include <stdlib.h>
#include <signal.h>
#include <time.h>
#include "include.h"
#define SHM_SIZE 1000
void handler(int);
void eatPellet();
void missPellet();
int main(int argc, char* argv[]) {
signal(SIGINT, handler);
attachSharedMemory();
srand(time(NULL));
int i = 1; // 1 - 19 are pellets
for (; i < 20; i++) {
int pelletPosition = rand() % 9 ; // random number from 0 - 9
if (shm[i] == -1){
// printf("hello %d \n", pelletPosition);
shm[i] = pelletPosition;
}
break;
}
while(1) {
printf("helloasd %d \n", shm[i]);
printf("i: %d \n", i);
if (shm[i] < 90) {
shm[i] += 10;
}
else if (shm[i] == shm[0]) {
eatPellet();
printf("Position: %d\n", shm[i] );
break;
// EATEN and KILL
}
else {
// KIll process, terminate
missPellet();
printf("Position: %d\n", shm[i] );
break;
}
// printf("%d\n",shm[i] );
i++;
sleep(1);
}
shmdt(shm);
return 0;
}
void handler(int num) {
shmdt(shm);
exit(1);
}
我查看了其他堆栈溢出问题,看来它们有问题,因为它们没有以NULL终止吗?我认为问题出在Pellets.c内,但我似乎无法弄清楚。谢谢。