Question

我是pytest的新手，正在努力通过它。我目前正在编写一个小型的CLI游戏，它将连续需要多个用户输入，但我不知道该怎么做。我读了很多解决方案，但没有设法使它起作用。

这是我的代码：

import React, { Component } from 'react';
import PropTypes from 'prop-types';
import InputBase from '@material-ui/core/InputBase';
import { withStyles } from '@material-ui/core/styles';
import { withRouter } from 'react-router-dom';
import { connect } from 'react-redux';
import { getAppInfo } from '../../actions/appActions.js';
import constants from '../../constants.js';

import { AppSearchBarInputStyles } from '../styles/Material-UI/muiStyles.js';
import AppNotFound from './AppNotFound.js';

import * as log from 'loglevel';
log.setLevel("debug")


class AppSearchBarInput extends Component {
  state = {
    appId: '',
    snackBarOpen: false
  }

  onChange = e => {
    this.setState({ appId: e.target.value });
  }

  onKeyDown = e => {
    const { appId } = this.state;
    const { found } = this.props.app;

    if (e.keyCode === constants.ENTER_KEY) {

      this.props.getAppInfo({ appId });
      if (found) {
        this.props.history.push('/moreInfo');
      } else {
        this.setState({
          snackBarOpen: true
        });
      }

      this.setState({
        appId: ''
      });
    }
  }

  handleCloseSnackBar = () => {
    this.setState({
      snackBarOpen: false
    });
  }

  render() {

    const { classes, app } = this.props;
    const { snackBarOpen } = this.state;
    const { found, appId } = app;
    let message = '';

    if (!found) {
      message = appId === '' ? constants.MESSAGES.APP_BLANK() : constants.MESSAGES.APP_NOT_FOUND(appId);
    }

    let displayWhenFoundIsUndefined = null;

    if (found === undefined) {
      displayWhenFoundIsUndefined = <div>Loading...</div>;
    } else {
      displayWhenFoundIsUndefined = <AppNotFound message={message}
                   open={!found}
                   onClose={this.handleCloseSnackBar}/>;
    }
    return (
      <div>
        <InputBase
          placeholder="Search…"
          classes={{
            root: classes.inputRoot,
            input: classes.inputInput,
          }}
          onChange={this.onChange}
          onKeyDown={this.onKeyDown}
          value={this.state.appId} />
        {displayWhenFoundIsUndefined}
      </div>
    )
  }
}

AppSearchBarInput.propTypes = {
  classes: PropTypes.object.isRequired
}

const mapStateToProps = state => ({
  app: state.app.app
});

const AppSearchBarWithStyles = withStyles(AppSearchBarInputStyles)(AppSearchBarInput);
const AppSearchBarWithStylesConnected = connect(mapStateToProps, { getAppInfo })(AppSearchBarWithStyles);
export default withRouter(AppSearchBarWithStylesConnected);

我只是想自动化这两个请求的用户输入。（即：将class Player: def __init__(self): self.set_player_name() self.set_player_funds() def set_player_name(self): self.name = str(input("Player, what's you name?\n")) def set_player_funds(self): self.funds = int(input("How much money do you want?\n"))和input "Bob"

的测试

有人可以帮忙吗？谢谢！

Answer 1

测试输入的相当优雅的方法是使用 monkeypatch 固定装置模拟输入文本。可以使用 lambda 语句和迭代器对象来处理多个输入。

def test_set_player_name(monkeypatch):
    # provided inputs
    name = 'Tranberd'
    funds = 100
    
    # creating iterator object
    answers = iter([name, str(funds)])

    # using lambda statement for mocking
    monkeypatch.setattr('builtins.input', lambda name: next(answers))

    player = Player()
    assert player.name == name
    assert player.funds == funds

monkeypatch 在 docs.pytest.org。
wiki.python.org 上的 Iterator object。

Pytest用户输入模拟

1 个答案: