Question

我是Django的新手，我遇到了一个问题。我有多种型号，需要针对地址的地址和电话号码。而且只有电话号码可以与某些型号关联。因此，我为“ 地址”和“ 电话号码”建立了多态关系。就像这里：

class PhoneNumber(SoftDeleteModel):
     phone_number = PhoneNumberField()
     content_type = models.ForeignKey(ContentType, on_delete=models.CASCADE)
     object_id = models.PositiveIntegerField()
     content_object = GenericForeignKey('content_type', 'object_id')
     created_at = models.DateTimeField(auto_now=False, auto_now_add=True)
     updated_at = models.DateTimeField(auto_now=True, auto_now_add=False)
     created_by = models.ForeignKey(get_user_model(), on_delete=models.CASCADE)

     def __str__(self):
         return self.phone_number.as_e164

class Address(SoftDeleteModel):
     house_number = models.CharField(max_length=255)
     street_number = models.CharField(max_length=255)
     area = models.CharField(max_length=255)
     city = models.CharField(max_length=255)
     country = models.CharField(max_length=255)
     content_type = models.ForeignKey(ContentType, on_delete=models.CASCADE)
     object_id = models.PositiveIntegerField()
     phone_number = GenericRelation(PhoneNumber)
     content_object = GenericForeignKey('content_type', 'object_id')
     created_at = models.DateTimeField(auto_now=False, auto_now_add=True)
     updated_at = models.DateTimeField(auto_now=True, auto_now_add=False)
     created_by = models.ForeignKey(get_user_model(), on_delete=models.CASCADE)

     def __str__(self):
          return str(self.house_number)+", "+str(self.street_number)+", "+self.area+", "+self.city+", "+self.country

这些是地址和电话号码的模型，我正在供应商中使用地址模型，例如：

class Vendor(SoftDeleteModel):
     vendor_name = models.CharField(max_length=500)
     vendor_phone = GenericRelation(PhoneNumber)
     vendor_address_detailed = GenericRelation(Address)
     vendor_contact_person = models.CharField(max_length=500)
     created_at = models.DateTimeField(auto_now=False, auto_now_add=True)
     updated_at = models.DateTimeField(auto_now=True, auto_now_add=False)
     created_by = models.ForeignKey(get_user_model(), on_delete=models.CASCADE)

     def __str__(self):
          return self.vendor_name

在为供应商进行管理员管理时，我只能获得地址模型中的地址，而不是 PhoneNumber ，如图中所示

管理类的代码如下：

class PhoneNumberAdmin(GenericTabularInline):
     model = PhoneNumber
     extra = 1
     exclude = ('deleted', 'created_by')

     def save_model(self, request, obj, form, change):
         obj.created_by = request.user
         super().save_model(request, obj, form, change)


class AddressAdmin(GenericStackedInline):
     model = Address
     extra = 1
     exclude = ('deleted', 'created_by')

     def save_model(self, request, obj, form, change):
         obj.created_by = request.user
         super().save_model(request, obj, form, change)


class VendorAdmin(admin.ModelAdmin):
     model = Vendor
     list_display = ('vendor_name', 'created_by', 'created_at_readable')
     inlines = (AddressAdmin, )
     exclude = ('deleted', 'created_by')

     def created_at_readable(self, obj):
         return naturaltime(obj.created_at)

     created_at_readable.empty_value_display = "???"

请帮助我使用Django Admin添加 PhoneNumber 。

编辑：

我想将电话号码与每个地址相关联。因此，在“管理电话号码”字段中，地址将位于Adress模型中，而在“供应商”中则不会。谢谢

Answer 1

在网上冲浪后，我发现了这个名为NestedAdmin的库。该库支持admin中几乎所有的嵌套关系。我要在此处发布其网址。

https://github.com/theatlantic/django-nested-admin

不过谢谢您的时间。

Answer 2

在VendorAdmin中添加电话号码的内联

 inlines = (AddressAdmin, PhoneNumberAdmin)

Django-在管理面板中显示具有内容类型的模型

2 个答案: