Question

当我通过App PhoneGap运行应用程序的代码时，我的应用程序将运行。但是，如果代码将其转换为apk并将其安装在我的android手机上，则启动相机并将照片上传到服务器的按钮将不起作用。我带给你代码：

<html>
    <head>
        <meta charset="UTF-8">
        <meta http-equiv="Content-Security-Policy" content="default-src *; style-src 'self' 'unsafe-inline'; script-src 'self' 'unsafe-inline' 'unsafe-eval'" />
        <title>My app</title>
<link href="css/bootstrap.min.css" rel="stylesheet">
        <!-- Script -->
        <script type="text/javascript" src="cordova.js" ></script>
        <script type='text/javascript' src='jquery-3.0.0.js' ></script>

    </head>
    <body>
        <div align="center" id="logo"><img src="img/logo.png" width="50%"></div>
        <div style="margin:0 auto; width:30%!important;text-align: center;">
            <img src="img/cam3.jpg" id='img' style="width: 100px; height: 100px;">
        </div><br/>
        <div style="width:100%; text-align:center; padding:10px;">


             <div class="text-center mt-4">
          <button id='but_take' type="button" class="btn btn-primary" >Cattura reperto</button>
        </div>
             <div style="margin-top: 30px; " class="text-center mt-4">

            <a type="button" class="btn btn-info" href="#" onclick="window.open('https://myserverexample.com/img.php', '_system');">Guarda reperti</a>
             </div>



        </div>
        <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
    <!-- Include all compiled plugins (below), or include individual files as needed -->
    <script src="js/bootstrap.min.js"></script>
    <script type='text/javascript'>

        $(document).ready(function(){

            // take picture from camera
            $('#but_take').click(function(){      
                navigator.camera.getPicture(onSuccess, onFail, { quality: 20,
                    destinationType: Camera.DestinationType.FILE_URL 
                });
            });



            // Change image source and upload photo to server
            function onSuccess(imageURI) {

                // Set image source
                var image = document.getElementById('img');
                image.src = imageURI  + '?' + Math.random();

                var options = new FileUploadOptions();
                options.fileKey = "file";
                options.fileName = imageURI.substr(imageURI.lastIndexOf('/') + 1);
                options.mimeType = "image/jpeg";

                var params = {};
                params.value1 = "test";
                params.value2 = "param";

                options.params = params;
                options.chunkedMode = false;
// load image to server
                var ft = new FileTransfer();
                ft.upload(imageURI, "http://myserverexample.com/load-image.php", function(result){
                    alert('image load ' );
                }, function(error){
                    alert('error : ' + JSON.stringify(error));
                }, options);

            }

            function onFail(message) {

                alert('No Image: ' + message);
            }

        });

        </script>
    </body>
</html>

我应该怎么做才能使代码在android上工作？有什么办法可以查看android上apk手机差距的错误吗？谢谢

PhoneGap-我的代码应用程序与Phonegapp应用程序一起运行，但在APK中不起作用

0 个答案: