我有2D项目,我希望能够左右左右移动相机...我找到了一个教程,通过滑动来移动相机,这样效果很好,但是如何设置移动相机的最大距离呢?
using System.Collections;
using System.Collections.Generic;
using UnityEngine;
public class TouchController : MonoBehaviour
{
float touchStart = 0f;
Vector3 cameraDestination;
public float cameraSpeed = 0.1f;
Camera m_MainCamera;
// Use this for initialization
void Start()
{
cameraDestination = Camera.main.transform.position;
}
// Update is called once per frame
void Update()
{
if (Input.GetMouseButtonDown(0))
{
touchStart = Input.mousePosition.x;
}
if (Input.GetMouseButtonUp(0))
{
float delta = Input.mousePosition.x - touchStart;
if (delta < -50f)
{
cameraDestination = new Vector3(Camera.main.transform.position.x + 500,
Camera.main.transform.position.y, Camera.main.transform.position.z);
// move the camera right
}
else if (delta > 50f){
cameraDestination = new Vector3(Camera.main.transform.position.x - 500,
Camera.main.transform.position.y, Camera.main.transform.position.z);
// move the camera left
}
}
if (Vector3.Distance(Camera.main.transform.position, cameraDestination) > 0.1f)
{
if (Camera.main.transform.position.x > cameraDestination.x)
{
Camera.main.transform.position = new Vector3(Camera.main.transform.position.x - cameraSpeed,
Camera.main.transform.position.y, Camera.main.transform.position.z);
}
else
{
Camera.main.transform.position = new Vector3(Camera.main.transform.position.x + cameraSpeed,
Camera.main.transform.position.y, Camera.main.transform.position.z);
}
}
}
}
答案 0 :(得分:2)
您的问题尚不清楚,但是我想您想为相机的位置设置一个限制。为此,您需要2个点-最小点(x =允许相机具有的最小X值,y =允许相机具有的最小Y值)和最高点(相同,但代表上限)。
if (cameraDestination.x < maxPosition.x && cameraDestination.x > minPosition.x) //Ensures the camera's X value is within the allowed range
if (cameraDestination.y < maxPosition.y && cameraDestination.y > minPosition.y) //Ensures the camera's Y value is within the allowed range
然后,每次移动相机时,请检查以下条件,然后再移动:
sudo apt remove jekyll
sudo apt-get --autoremove
which jekyll
sudo rm /bin../jekyll