Question

我在数组中有一个设置为字符串的字符串

const LANGUAGES = [    "tamil",    "hindi",    "punjabi",    "malayalam",    "telugu",    "marati",    "sinhala"  ];

目标 string 在引号（例如“文本”）中将具有不可预测的逗号分隔值的字符串序列

可能的例子是

const text = '["CineIndia","ENG SUBS","IR","SAVER","TAMIL"]'

const text1 = '["SAVER","NFT","CineIndia","ENG SUBS","Hindi","IR","SAVER"]'

我尝试遍历LANGUAGES并使用indexOf

如何从LANGUAGES或text之类的东西中提取text1中的值

我尝试遍历LANGUAGES并使用indexOf。但这有点说明性，我正在寻找一种更智能的方法来实现相同的目的

Answer 1

一种实现方法是将.indexOf()与.toLowerCase()或.toUpperCase()结合使用，因为您要搜索的内容与语言列表的情况不同。

const LANGUAGES = ["tamil",    
                   "hindi",    
                   "punjabi",    
                   "malayalam",    
                   "telugu",    
                   "marati",    
                   "sinhala"  ];

const text = '["CineIndia","ENG SUBS","IR","SAVER","TAMIL"]';

const text1 = '["SAVER","NFT","CineIndia","ENG SUBS","Hindi","IR","SAVER"]';

LANGUAGES.forEach(function(lang){
  if (text.toLowerCase().indexOf(lang)>-1) {
    console.log('the constant [text] contains ' + lang);
  }
  if (text1.toLowerCase().indexOf(lang)>-1) {
    console.log('the constant [text1] contains ' + lang);
  }
  
});

Answer 2

使用JSON.parse将字符串返回数组：

const text1 = '["SAVER","NFT","CineIndia","ENG SUBS","Hindi","IR","SAVER"]'
console.log(JSON.parse(text1))

现在，您可以使用过滤器了：

const LANGUAGES = [    "tamil",    "hindi",    "punjabi",    "malayalam",    "telugu",    "marati",    "sinhala"  ];
const text1 = '["SAVER","NFT","CineIndia","ENG SUBS","Hindi","IR","SAVER"]';
const txtArr = JSON.parse(text1)
const filteredTxt1 = txtArr.filter(x => LANGUAGES.includes(x.toLowerCase()))
console.log(filteredTxt1)

Answer 3

好吧，所以您正在尝试从定义的语言列表中正确获取文本数组的语言吗？

如果是，这是您的答案：

const LANGUAGES = ["tamil", "hindi", "punjabi", 
    "malayalam", "telugu", "marati", "sinhala"];
const text = '["CineIndia","ENG SUBS","IR","SAVER","TAMIL"]'
const text1 = '["SAVER","NFT","CineIndia","ENG SUBS","Hindi","IR","SAVER"]'
function getLang(text) {
  const array = JSON.parse(text)
  let lang = -1
  const languages = LANGUAGES.map(x => x.toLowerCase())
  for (var i = 0; i < array.length; i++) {
    if (languages.indexOf(array[i].toLowerCase()) != -1) {
      lang = languages.indexOf(array[i].toLowerCase())
   }
 }
 return LANGUAGES[lang]
}
console.log(getLang(text))
console.log(getLang(text1))

使用字符串数组提取子字符串

3 个答案: