Question

我想在！=中使用多个单词，但我一生无法理解或用谷歌搜索。任何人都可以帮忙，并解释为什么我不能做到这样：！=“否”！=“否”！=“ n”！=“ N”：等等等等

answers = ["Yes", "Not now not ever.", "Unclear answer, try again.", "Maybe.", "Probably not.", "Try again later.",
           "My sources says no.", "My sources says yes.", "Only when there is a full moon.", "It is certain.",
           "Cannot predict now.", "Outlook not so good", "Very doubtful.", "You may rely on it.",
           "Yes - definitely.", "As I see it, yes.", "Signs point to yes."]    

while str(input("Do you want to ask the Magic 8Ball a question?  Yes or No?  ")) != "No" != "no": # <-- problematic line
    str(input("Ask the mighty 8Ball your question:  "))
    randomanswer = answers[random.randint(0, len(answers) -1)]
    print("\n","The Magic 8Ball says: ")
    print(randomanswer, "\n")    
else:
    return

Answer 1

您可以使用元组值，例如

while foo not in ('No', 'no', 'N', 'n'):
    # code

或

while foo.lower() not in ('no', 'n'):
    # code

如果有大量的前哨，set的执行速度将比元组快（对于少量值，散列是不值得的）。

您可能还想研究re模块，以进行更复杂的模式匹配。

Answer 2

尝试

while str(input("Do you want to ask the Magic 8Ball a question?  Yes or No?  ")) not in ["No", "no"]

Answer 3

您正在寻找一种将条件语句链接在一起的方法。不幸的是，您无法以尝试的方式进行操作。但是，您可以使用and和or将它们链接在一起，这通常是这样做的。例如：

userinput = str(input("Do you want to ask the Magic 8Ball a question?  Yes or No?  "))

while userinput != "No" and userinput != "no":
    # have to get user input again at end of loop

但是更好的方法是找到如何在逻辑上将其转换为单个条件，在这种情况下，请在用户输入上使用lower：

userinput = str(input("Do you want to ask the Magic 8Ball a question?  Yes or No?  "))
userinput = userinput.lower() # make it lowercase

while userinput != "no":
    # have to get user input again at end of loop

最后，您可以使用random.choice从答案数组中提供随机元素。

Answer 4

将有问题的行更改为：

while input("Do you want to ask the Magic 8Ball a question?  Yes or No?  ").strip().lower() != "no":

通过这种方式，您可以将输入字符串转换为小写（lower()），同时还删除了用户可能在其中键入的任何空格（strip()）

然后，如果用户键入：“否”，lower()会将其转换为所有小写字母“否”，然后将其检查到您的!= 'no'。

在input()中键入的任何内容都是字符串，因此可以省略str()。

Python-在！=中使用多个单词

4 个答案: