我正在尝试做一个简单的通知功能 但是每次我触发该函数时,都会出现错误
TypeError:无法读取未定义的属性“ params” 在export.sendNotification.functions.database.ref.onWrite(/user_code/index.js:23:32) 在cloudFunctionNewSignature(/user_code/node_modules/firebase-functions/lib/cloud-functions.js:105:23) 在cloudFunction(/user_code/node_modules/firebase-functions/lib/cloud-functions.js:135:20) 在/var/tmp/worker/worker.js:758:24 在process._tickDomainCallback(internal / process / next_tick.js:135:7)
或者我得到错误
TypeError:无法读取未定义的属性“ user_id”
我从here那里得到了答案
但是我一点也没有帮助,我也找不到问题。这是我的代码
'use strict'
const functions = require('firebase-functions');
const admin = require('firebase-admin');
admin.initializeApp();
exports.sendNotification = functions.database.ref('/notifications/{user_id}/{notification_id}').onWrite((change,context) => {
const user_id = event.params.user_id;
const notification_id = event.params.notification_id;
console.log('We have a notification from : ', user_id);
if(!context.data.val()){
return console.log('A Notification has been deleted from the database : ',
notification_id);
}
const fromUser =admin.database().ref(`/notifications/${user_id}/${notification_id}`).once('value');
return fromUser.then(fromUserResult => {
const from_user_id = fromUserResult.val().from;
console.log('You have new notification from : ', from_user_id);
const userQuery = admin.database().ref(`Users/${from_user_id}/name`).once('value');
const deviceToken = admin.database().ref(`/Users/${user_id}/device_token`).once('value');
return Promise.all([userQuery, deviceToken]).then(result => {
const userName = result[0].val();
const token_id = result[1].val();
const payload = {
notification: {
title : "New Friend Request",
body: `${userName} has sent you request`,
icon: "default",
click_action : "none"
},
data : {
from_user_id : from_user_id
}
};
return admin.messaging().sendToDevice(token_id, payload).then(response => {
return console.log('This was the notification Feature');
});
});
});
});
答案 0 :(得分:2)
您从未定义event
,因此未定义。您正在尝试访问未定义变量的属性。您是说context.params.user_id
吗?
(您可能正在使用一个过时的教程。我在Stack Overflow上经常看到这样的错误的“ sendNotification”功能。让作者知道。)