Question

我正在尝试编写一个使用tcp套接字与设备通信的C / C ++应用程序。我的应用程序充当服务器套接字。从设备套接字接收数据时，服务器使用send（）函数对设备做出响应：

ssize_t send(int sockfd, const void *buf, size_t len, int flags);

缓冲区长度（〜4kB）大于MTU（1500字节）。 TCP将其分为较小的程序包。我用wireshark捕获数据包。我看到tcp数据包之间的时间延迟是0.2-0.3s。如果我发送大数据（〜100Mb），则花费的时间太长（几个小时）。
我已经尝试通过setsockopt启用TCP_NODELAY，TCP_QUICKACK和TCP_CORK，但仍然无法减少时间延迟。
你们能帮我解决这个问题吗？
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编辑：这是我的代码：

#include <iostream>
#include <sys/socket.h>
#include <netinet/in.h>
#include <netinet/tcp.h>
#include <arpa/inet.h>
#include <unistd.h>
#include <string.h>

void createServerSocket();
void acceptConnect(int serverSock);
void receiveDataFromSocket(int socket);
void sendDataOverSocket(int clientSock);

void createServerSocket() {
    int serverSockFd = socket(AF_INET6, SOCK_STREAM, IPPROTO_TCP);
    std::string address = "fd53:7cb8:383:5::68";
    int port = 42654;

    if (serverSockFd < 0)
    {
        printf("Create Server socket fail");
        return;
    }
    struct sockaddr_in6 serverAddress;
    (void)memset(&serverAddress, 0, sizeof(sockaddr_in6));
    serverAddress.sin6_family = AF_INET6;
    serverAddress.sin6_port = htons(port);
    int result = inet_pton(AF_INET6, address.c_str(), &serverAddress.sin6_addr);

    if (result <= 0)
    {
        printf("inet_pton() failed portnumber: %d, address: %s \n", port, address.c_str());
        return;
    }

    // setting socket options
    int flag = 1;

    if(setsockopt(serverSockFd,IPPROTO_TCP,TCP_QUICKACK  ,(char *)&flag,sizeof(flag)) == -1)
    {
        printf("setsockopt TCP_QUICKACK failed for server socket on address %s \n", address.c_str());
    }
    if(setsockopt(serverSockFd,IPPROTO_TCP,TCP_CORK,(char *)&flag,sizeof(flag)) == -1)
    {
        printf("setsockopt TCP_CORK failed for server socket on address %s \n", address.c_str());
    }
    if(setsockopt(serverSockFd,IPPROTO_TCP,TCP_NODELAY,(char *)&flag,sizeof(flag)) == -1)
    {
        printf("setsockopt TCP_NODELAY failed for server socket on address %s \n", address.c_str());
    }

    result = bind(serverSockFd, (struct sockaddr*)&serverAddress, sizeof(sockaddr_in6));

    if (result != 0)
    {
        printf("bind() failed portnumber: %d, address: %s \n", port, address.c_str());
        return ;
    }

    result = listen(serverSockFd, 10);
    if (result != 0) {
        printf("listen() failed portnumber: %d, address: %s \n", port, address.c_str());
        return ;
    }

    acceptConnect(serverSockFd);
}

void acceptConnect(int serverSock)
{
    struct sockaddr_in6 clientAddress;
    socklen_t len = sizeof(sockaddr_in6);
    memset(&clientAddress, 0, sizeof(sockaddr_in6));

    const int clientSocket = accept(serverSock, (struct sockaddr*)&clientAddress, &len);

    if(clientSocket >= 0) {
        char str_addr[INET6_ADDRSTRLEN];
        inet_ntop(AF_INET6, &(clientAddress.sin6_addr),
                  str_addr, sizeof(str_addr));
        printf("New connection from: %s:%d ...\n", str_addr, ntohs(clientAddress.sin6_port));
        receiveDataFromSocket(clientSocket);
    }
}

void receiveDataFromSocket(int socket)
{
    int SOCKET_BUFFER_MAX_SIZE = 8*1024;

    char buffer[SOCKET_BUFFER_MAX_SIZE];
    memset(buffer, '\0', SOCKET_BUFFER_MAX_SIZE);
    //Receive data from sock
    while (true) {
        int dataLen = recv(socket, buffer, SOCKET_BUFFER_MAX_SIZE, 0);
        printf("Receive data from socket: %d, msgLength = %d\n", socket, dataLen);
        sendDataOverSocket(socket);
    }
}

void sendDataOverSocket(int clientSock)
{
    int dataLen = 4*1024 + 7;
    char *buf = new char[dataLen];
    memset(buf, 'a', 4*1024 + 7);
    int ret;
    ret = send(clientSock, buf, dataLen, 0);

    if (ret <= 0) {
        printf("ERROR Send message over socket");
        return;
    }

    int error_code;
    socklen_t error_code_size = sizeof(sockaddr_in6);
    getsockopt(clientSock, SOL_SOCKET, SO_ERROR, &error_code, &error_code_size);
    printf("Error code size: %d, error code: %d\n", error_code_size, error_code);
}

Answer 1

我认为您已经超出了TCP发送缓冲区，正在按顺序接收和发送，如果另一端没有从套接字读取数据足够快，您将在每个send（）操作中等待，直到发送缓冲区中有空间为止

检查您发送的信息是否比接收的信息多，我怀疑recv（）正在读取小块数据（由于MTU），但是每个循环中大约发送4KB，因此您的recv / send调用没有达到适当的平衡。

套接字通过send（）发送的TCP数据包缓慢

1 个答案: