我已经为我的编程课写出了所有代码。这项工作需要我们创建一个程序，该程序允许用户在计算机上玩剪刀石头布。我们需要有单独的方法来获取计算机的选择，用户的选择，检查用户的选择是否有效以及确定比赛的获胜者。如果一场比赛没有平局，我们需要打印出比赛获胜的原因，例如。 “剪刀剪纸”，并打印出获胜者。一切正常，除非用户获胜，否则永远不会计算或宣布。例如，而不是打印：
计算机的选择是艰难的。用户的选择是纸张。纸覆盖岩石。用户赢了！
它打印：
计算机的选择是艰难的。用户的选择是纸张。纸覆盖了岩石。
import java.util.Scanner;
import java.util.Random;
public class FinalRockPaperScissors {
//Computer's Choice
public static int computersChoice (int options) {
Random randGen = new Random();
int computerValue = randGen.nextInt(options)+1;
System.out.println(computerValue); //FOR TESTING ONLY
return computerValue;
}
//Player's Choice
public static int usersChoice () {
Scanner scnr = new Scanner(System.in);
System.out.print("Enter 1 for rock, 2 for paper, or 3 for scissors: ");
int userValue = scnr.nextInt();
if (isValid(userValue) == true) {
return userValue;
}
else {
userValue = 0;
return userValue;
}
}
//Check for valid user input
public static boolean isValid (int userInput){
if (userInput == 1 || userInput == 2 || userInput == 3) {
return true;
}
else {
return false;
}
}
//Checking winner
public static char determineWinner () {
char win;
int computerValue = computersChoice(3);
int userValue = usersChoice();
//print computer choices
if (computerValue == 1) {
System.out.println("The computer's choice was rock.");
}
else if (computerValue == 2) {
System.out.println("The computer's choice was paper.");
}
else if (computerValue == 3){
System.out.println("The computer's choice was scissors.");
}
//print user choices
if (userValue == 1) {
System.out.println("The user's choice was rock.");
}
else if (userValue == 2) {
System.out.println("The user's choice was paper.");
}
else if (userValue == 3){
System.out.println("The user's choice was scissors.");
}
//check who won
if (computerValue == 1) { //rock vs
if (userValue == 2) { //paper
System.out.println("Paper wraps Rock.");
return win = 'b';
}
else if (userValue == 3) { //scissors
System.out.println("Rock smashes Scissors.");
return win = 'a';
}
else if (userValue == 1){ //rock
return win = 'c';
}
else {
System.out.println("The user chose an invalid number. This round will be ignored.");
return win = 'd';
}
}
else if (computerValue == 2) { //paper vs
if (userValue == 2) { //paper
return win = 'c';
}
else if (userValue == 3) { //scissors
System.out.println("Scissors cuts Paper.");
return win = 'b';
}
else if (userValue == 1){ //rock
System.out.println("Paper wraps Rock.");
return win = 'a';
}
else {
System.out.println("The user chose an invalid number. This round will be ignored.");
return win = 'd';
}
}
else { //scissors vs
if (userValue == 2) { //paper
System.out.println("Scissors cuts Paper.");
return win = 'a';
}
else if (userValue == 3) { //scissors
return win = 'c';
}
else if (userValue == 1){ //rock
System.out.println("Rock smashes Scissors.");
return win = 'b';
}
else {
System.out.println("The user chose an invalid number. This round will be ignored.");
return win = 'd';
}
}
}
public static void main(String[] args) {
int userWins = 0;
int computerWins = 0;
int ties = 0;
int error = 0;
//for (int i = 0; i < 1; i++) { //5 for testing purposes
if (determineWinner() == 'a') {
System.out.println("The computer wins!");
System.out.println("");
computerWins++;
}
else if (determineWinner() == 'b') {
System.out.println("The user wins!");
System.out.println("");
userWins++;
}
else if (determineWinner() == 'c'){
System.out.println("The game is tied!");
System.out.println("");
ties++;
}
else {
error++;
}
//}
System.out.println("The number of ties is " + ties);
System.out.println("The number of user wins is " + userWins);
System.out.println("The number of computer wins is " + computerWins);
//output final winner
if (computerWins > userWins) {
System.out.println("Computer is the winner.");
}
else if (userWins > computerWins) {
System.out.println("User is the winner.");
}
else {
if (userWins == computerWins) {
System.out.println("User is the winner.");
}
else if (computerWins == ties) {
System.out.println("Computer is the winner.");
}
}
}
}
经过一些测试，我发现问题可能出在我的userchoice()方法上。如果我禁用此方法并为用户设置一个值，那么一切都会正常进行。问题是我不知道为什么它不起作用，结果我无法修复它。
答案 0 :(得分：0)
在main函数中，您每次测试if条件时都会调用determineWinner()。正确的方法是将返回的值存储在变量中，然后检查该变量是否为“ a”，“ b”或“ c”。例如：
char result = determineWinner();
if (result == 'a') {
System.out.println("The computer wins!");
System.out.println("");
computerWins++;
}
答案 1 :(得分：0)
我认为您是Java的新手，并且让我们开始向您展示您在此代码中的错误，您多次致电determineWinner()，但这并不是那样，因为您重复了游戏四次确定一次结果，因此您应该调用一次并获取返回值并检查该值，例如：-
char result = determineWinner(); //Play the game and get the result
// use it in conditions
if (result == 'a') {
System.out.println("The computer wins!");
System.out.println("");
computerWins++;
}
else if (result == 'b') {
System.out.println("The user wins!");
System.out.println("");
userWins++;
}
else if (result == 'c'){
System.out.println("The game is tied!");
System.out.println("");
ties++;
}
else {
error++;
}