Question

这是我在这个平台上遇到的第一个问题，我是Python编码的新手。这个问题是HackkerRank中的一个挑战。您能为我的编码提出任何解决方案吗？它给出了运行时错误：

n=int(input())
phoneBook={}
pb=[]
list1=[]
for i in range(n):
  k=str(input())
  pb.append(k)
  list1.append(k.split(" "))
  for j in range (2):
    phoneBook[list1[i][0]]=list1[i][1]
b='at'
try:
 while b != "":
  b=str(input())
  if any(b in s for s in phoneBook):
   print(b,"=",phoneBook[b],sep='')
  else:
   print("Not found")
except EOFError:
    pass

先谢谢了。

Answer 1

缩短的代码-您使用了太多的中间列表-它们都需要时间来构造，填充和使用：

# create the phone book
d = {}
for n in range(int(input())):

    # repeat input() and strip/split/strip it into the dict
    # use list decomposition instead of a list over a range of indext list values
    name,number = [x.strip() for x in input().strip().split()]
    d[name]=number

# read and produce numbers until done
while True:
    try:
        q = input()

        # no need for if any(b in s for s in phoneBook):
        # dictionary is fast for testing if key in it
        # I would prefer dict.get(key,default) but for the wanted 
        # output this is easier / better
        if q in d:
            # use string formating
            print("{}={}".format(q, d[q]))
        else:
            print("Not found")
    except EOFError:
        break

为什么我的python编码给运行时错误？

1 个答案: