响应式两个渐变对角线按钮

时间:2018-11-23 12:04:12

标签: css css3 linear-gradients

我有一个对角线分开的按钮。我想为每侧添加不同的渐变。我试过使用:before和:after分成两部分,但这需要旋转或倾斜,这意味着更改deg的响应不是很好。基本上,无论宽度和高度如何,我都需要在中心处留一个截点,以使左上角和右下角保持在不同的断点。有更好的方法吗?

.btn {
  background-image: linear-gradient(47deg, #f09 0%, #A09 100%);
  display: inline-block;
  font-size: 1.6rem;
  text-decoration: none;
  text-align: center;
  cursor: pointer;
  max-width: 32rem;
  width: 100%;
  padding: 2.6rem 1rem;
  color: $white;
  text-transform: uppercase;
  vertical-align: middle;
  overflow: hidden;
  position: relative;
  z-index: 1;
}

.btn:after {
  content: '';
  width: 100%;
  left: 0%;
  right: 0;
  bottom: 0;
  top: 48%;
  background-image: linear-gradient(47deg, #A09 0%, #f09 100%);
  position: absolute;
  transform: skewY(14deg);
  height: 200%;
  z-index: -1;
}
<a href="" class="btn">Button</a>

1 个答案:

答案 0 :(得分:0)

您可以在按钮内保留一个渐变,然后在伪元素上考虑clip-path以创建三角形并应用第二个渐变:

.btn {
  background-image: linear-gradient(47deg, yellow 0%, #A09 100%);
  display: inline-block;
  font-size: 1.6rem;
  text-decoration: none;
  padding: 2.6rem 1rem;
  color: #fff;
  text-transform: uppercase;
  position: relative;
  z-index: 0;
}

.btn:after {
  content: '';
  position:absolute;
  left: 0;
  right: 0;
  bottom: 0;
  top: 0;
  background-image: linear-gradient(47deg, red 0%, blue 100%);
  -webkit-clip-path:polygon(0 0,100% 0,100% 100%);
  clip-path:polygon(0 0,100% 0,100% 100%);
  z-index: -1;
}
<a href="" class="btn">Button</a>
<a href="" class="btn">Another Button</a>