Question

我有134个节点。已经执行了十四种不同的分析（运行）。对于所有134个节点，每个运行都有保存为字典的值。每个节点都保存了150个时间步长的值（每个节点150个值）。例如，运行1被保存为字典（10个时间步长），即节点A，（0,1,0,5,6，7，8， 1，0,6）和节点B，（1,2,3,4,5,7，6，8,9,1）。同样，运行2将另存为字典。我可以将这些值导出到excel工作表，但这些值将另存为（0,1,0,5,6，7，8，1，1,0,6）。我只希望将每个节点的前三个值导出到三个单独的列中的excel工作表（而不是所有10个值）

如何导出运行1和运行2的每一列中的各个值，并将其保存在Excel工作表中？

代码，该代码将保存一个Excel工作表，其中所有值都列在一栏中：

run1, run2, run3, run4, run5, run6, run7, run8, run9, run10, run11, run12, run13, run14 = data # each run has 5 values for 2 variables
 df = pd.DataFrame.from_dict(data)
 df.to_excel("data.xlsx")

运行此代码时，df_1= df.loc[:, pd.IndexSlice[:, ['Value 1', 'Value 3', 'Value 5']]]

我遇到以下错误：

TypeError                                 Traceback (most recent call last)
<ipython-input-84-8d2d90289161> in <module>()
----> 1 df_1= df.loc[:, pd.IndexSlice[:, ['Value 1', 'Value 3', 'Value 5']]]

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in __getitem__(self, key)
   1308 
   1309         if type(key) is tuple:
-> 1310             return self._getitem_tuple(key)
   1311         else:
   1312             return self._getitem_axis(key, axis=0)

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _getitem_tuple(self, tup)
    794     def _getitem_tuple(self, tup):
    795         try:
--> 796             return self._getitem_lowerdim(tup)
    797         except IndexingError:
    798             pass

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _getitem_lowerdim(self, tup)
    920         for i, key in enumerate(tup):
    921             if is_label_like(key) or isinstance(key, tuple):
--> 922                 section = self._getitem_axis(key, axis=i)
    923 
    924                 # we have yielded a scalar ?

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _getitem_axis(self, key, axis)
   1470                     raise ValueError('Cannot index with multidimensional key')
   1471 
-> 1472                 return self._getitem_iterable(key, axis=axis)
   1473 
   1474             # nested tuple slicing

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _getitem_iterable(self, key, axis)
   1034     def _getitem_iterable(self, key, axis=0):
   1035         if self._should_validate_iterable(axis):
-> 1036             self._has_valid_type(key, axis)
   1037 
   1038         labels = self.obj._get_axis(axis)

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/core/indexing.py in _has_valid_type(self, key, axis)
   1390 
   1391             # TODO: don't check the entire key unless necessary
-> 1392             if len(key) and np.all(ax.get_indexer_for(key) < 0):
   1393 
   1394                 raise KeyError("None of [%s] are in the [%s]" %

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/indexes/base.py in get_indexer_for(self, target, **kwargs)
   2384         """ guaranteed return of an indexer even when non-unique """
   2385         if self.is_unique:
-> 2386             return self.get_indexer(target, **kwargs)
   2387         indexer, _ = self.get_indexer_non_unique(target, **kwargs)
   2388         return indexer

/home/MBIAL/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/pandas/indexes/base.py in get_indexer(self, target, method, limit, tolerance)
   2284                                  'backfill or nearest reindexing')
   2285 
-> 2286             indexer = self._engine.get_indexer(target._values)
   2287 
   2288         return _ensure_platform_int(indexer)

pandas/index.pyx in pandas.index.IndexEngine.get_indexer (pandas/index.c:6077)()

pandas/src/hashtable_class_helper.pxi in pandas.hashtable.PyObjectHashTable.lookup (pandas/hashtable.c:14050)()

TypeError: unhashable type

谢谢

Priya

Answer 1

对concat使用字典理解，然后按slicers对列中的<main id="content" role="main"> <div class="container" style="background-color: bisque; height: 1000px;"></div> <div style="text-align: center"> <img src="assets/header-img.jpg"> </div> </main>进行过滤：

MultiIndex

Answer 2

这将起作用：

通过以下方法将一列中的值列表拆分为多列：

df[['Value1','Value2','Value3','Value4','Value5','Value6']] = pd.DataFrame(df.A.values.tolist(), index= df.index)
选择所需的列：

df = df[['Value1','Value3','Value6']]
写入csv

import pandas as pd

df.to_csv("Output.csv")

Answer 3

由于我没有标题的值，因此使用以下代码找到了我感兴趣的节点的值位置：

df_1 = df_1.iloc [:, [节点1]]

运行此代码时，它给出了节点1的开始和停止位置。因此，我在jezrael提供的上述代码中给出了这一行，并将结果保存到excel工作表中。

在jezrael代码中将此行替换为上面的行：

df = df.loc [:, pd.IndexSlice [:, ['Value 1'，'Value 3'，'Value 5']]]

@jezrael和Rahul Agarwal谢谢您的所有帮助

从字典到Excel工作表的值

3 个答案: