Question

我想添加第三个参数，它将文件名从上到下或从下到上更改，但是在这第三个参数中，我想指定必须更改哪个文件名？这个脚本怎么了？预先谢谢你。

#!/bin/bash

if test "$1" = "lower" && test "$2" = "upper"
then
    for file in *; do
        if [ $0 != "$file" ] && [ $0 != "./$file" ]; then
        mv "$file" "$(echo $file | tr [:lower:] [:upper:])";
        fi
fi
done

elif test "$1" = "upper" && test "$2" = "lower"
then
    for file in *; do
    if [ $0 != "$file" ] && [ $0 != "./$file" ]; then
    mv "$file" "$(echo $file | tr [:upper:] [:lower:])";
    fi
done
fi

if [ "$1" = "lower" ] && [ "$2" = "upper" ] && [ "$3" = "$file" ]; 
then
    for file in * ; do
    if [ $0 != "$file" ] && [ $0 != "./$file" ]; then
    mv "$file" "$(echo $file | tr [:lower:] [:upper:])";
    fi
done
fi

Answer 1

如果我猜对了你想要的东西，请尝试

#!/bin/bash

case $1:$2 in
 upper:lower | lower:upper ) ;;
 *) echo "Syntax: $0 upper|lower lower|upper files ..." >&2; exit 1;;
esac

from=$1
to=$2
shift; shift
for file; do
    mv "$file" "$(echo "$file" | tr "[:$from:]" "[:$to:]")"
done

这具有明显的优势，它允许三个以上的参数，其中前两个指定要执行的操作。

还请注意我们如何始终对包含文件名的字符串加引号。另请参见When to wrap quotes around a shell variable?

以上脚本实际上也应与/bin/sh一起使用；我们不使用任何仅Bash功能，因此它应在任何POSIX sh下运行。

但是，更好的设计可能是使用一个选项来确定要应用的映射，并简单地接受（可能为空）选项列表和文件名参数列表。然后，您也可以使用内置的Bash parameter expansion。但是，大小写转换参数扩展操作仅在Bash 4中可用。

#!/bin/bash

op=',,'
# XXX FIXME: do proper option parsing
case $1 in -u) op='^^'; shift;; esac

for file; do
    eval mv "\$file" "\${file$op}"
done

默认情况下，这会转换为小写，如果在文件名前输入-u，则会切换为大写。

在这两个脚本中，我们都使用for file作为for file in "$@"的简写，即，我们遍历（剩余的）命令行参数。也许这就是您想要的细节。

Answer 2

如果 I 严重误解，请原谅我，但我认为您可能误解了参数传递的工作原理。

named / numbered参数表示您在命令行中按顺序位置传递的值。从理论上讲，每个值都可以具有可卡在字符串中的任何值。您不需要第三个参数，只需第三个值。

让我们尝试一个示例。

#! /bin/env bash

me=${0#*/} # strip the path
use="
   $me { upper | lower } file

   changes the NAME of the file given to be all upper or all lower case.

"
# check for correct arguments
case $# in
2) : exactly 2 arguments passed - this is correct ;;
*) echo "Incorrect usage - $me requires exactly 2 arguments $use" >&2
   exit 1 ;;
esac

declare -l lower action # these variables will downcase anything put in them
declare -u upper        # this one will upcase anything in it
declare newname         # create a target variable with unspecified case

action="$1"             # stored the *lowercased* 1st argument passed as $action
case $action in         # passed argument has been lowercased for simpler checking
upper) upper="$2"       # store *uppercased* 2nd arg.
       newname="$upper" # newname is now uppercase.
       ;;
lower) lower="$2"       # store *lowercased* 2nd arg.
       newname="$lower" # newname is now lowercase.
       ;;
    *) echo "Incorrect usage - $me requires 2nd arg to be 'upper' or 'lower' $use" >&2
       exit 1 ;;
esac

if [[ -e "$2" ]]        # confirm the argument exists
then echo "Renaming $2 -> $newname:"
     ls -l "$2"
     echo " -> "
     mv "$2" "$newname" # rename the file
     ls -l "$newname"
else echo "'$2' does not exist. $use" >&2
     exit 1
fi

Answer 3

首先，此脚本存在缩进问题，首先检查条件是否应该在fi之前出现

下面是正确的。

if test "$1" = "lower" && test "$2" = "upper"
then

  for file in *; do
      if [ $0 != "$file" ] && [ $0 != "./$file" ]; then
      mv "$file" "$(echo $file | tr [:lower:] [:upper:])";
      fi
  done
fi

第二个您问的问题：

#/bin/bash -xe 

[ $# -ne 3 ] && echo "Usage: {lower} {upper} {fileName} " && exit 1 
if [ "$1" = "lower" ] && [ "$2" = "upper" ] && [ -f "$3" ]; 
then 
  mv "$3" "$(echo $3 | tr [:lower:] [:upper:])"; 
fi

希望这会有所帮助。

如何在此bash脚本中添加第三个参数？

3 个答案: