有关Java UDP与多线程通信的问题

时间:2018-11-23 07:25:02

标签: java multithreading sockets udp

我现在正在研究Java网络编程,我编写了一个程序,客户端向服务器发送当前时间的30倍,服务器将创建一个新线程来解析接收到的UDP数据包,并在服务器收到UDP时向客户端提供反馈包。

问题是,在我运行代码之后,服务器可以接收UDP数据包并创建一个新线程,但是似乎DatagramSocketDatagramPacket没有传递给该线程。因此,线程无法向客户端提供反馈,因此客户端在发送第一个UDP数据包后将一直等待。

我的代码在这里:

服务器

public class MulUDPServer {
public static void main(String[] args) {
    DatagramSocket socket = null; 
    DatagramPacket receivedPacket; 
    final int PORT = 10010; 
    byte[] b = new byte[1024];
    receivedPacket = new DatagramPacket(b, b.length);
    try {
        socket = new DatagramSocket(PORT);
        System.out.println("Server start!");
        while (true) {
            // receive the packet from server
            socket.receive(receivedPacket);
            // to check if Server get the packet
            System.out.println(new String(receivedPacket.getData(), 0, receivedPacket.getLength()));
            // start the thread to handle the packet we have got
            Thread thread = new Thread(new LogicThread(socket, receivedPacket));
            thread.start();
        }
    } catch (Exception e) {
        e.printStackTrace();
    } finally {
        try {
            // close the connection
            socket.close();
        } catch (Exception e) {
        }
    }
}

线程

public class LogicThread implements Runnable {

DatagramSocket socket = null;
DatagramPacket receivedPacket = null;

public LogicThread(DatagramSocket socket, DatagramPacket receivedPacket) {
    this.socket = socket;
    this.receivedPacket = receivedPacket;
}

public void run() {
    try {
        // to test if a thread have been set up
        System.out.println("a thread have been set up");
        byte[] data = receivedPacket.getData();
        int len = receivedPacket.getLength();
        // get the client IP
        InetAddress clientAddress = receivedPacket.getAddress();
        // get the client port
        int clientPort = receivedPacket.getPort();
        // print the info about received packet
        System.out.println("Client's IP:" + clientAddress.getHostAddress());
        System.out.println("Client's port:" + clientPort);
        System.out.println("The info:" + new String(data, 0, len));
        // feedback to Client
        byte[] b = "OK".getBytes();
        DatagramPacket sendPacket = new DatagramPacket(b, b.length, clientAddress, clientPort);
        // send
        socket.send(sendPacket);
    } catch (Exception e) {
        e.printStackTrace();
    }
}
}

客户

public class MulUDPClient {
public static void main(String[] args) {
        DatagramSocket socket = null; 
        DatagramPacket sendPacket; 
        DatagramPacket receivedPacket; 
        String serverHost = "localhost"; 
        int serverPort = 10010; 
        try {
            socket = new DatagramSocket();
            InetAddress address = InetAddress.getByName(serverHost);
            byte[] b = new byte[1024];
            receivedPacket = new DatagramPacket(b, b.length);
            System.out.println("Client ready!");
            for (int i = 0; i < 30; i++) {
                // get the current time
                Date d = new Date(); 
                String content = d.toString(); 
                byte[] data = content.getBytes();
                sendPacket = new DatagramPacket(data, data.length, address, serverPort);
                socket.send(sendPacket);
                System.out.println("already send time");
                Thread.sleep(10);

                // receive packet from Server
                socket.receive(receivedPacket);
                byte[] response = receivedPacket.getData();
                int len = receivedPacket.getLength();
                String s = new String(response, 0, len);
                System.out.println("the feedback from Server:" + s);
            }
        } catch (Exception e) {
            e.printStackTrace();
        } finally {
            try {
                // close the connection
                socket.close();
            } catch (Exception e) {
            }
        }
    }
}

在两个终端中分别运行服务器和客户端后的**结果**:

服务器

Server start!
Fri Nov 23 14:52:02 CST 2018
a thread have been set up

客户

Client ready!
already send time

从我们知道的结果来看,客户端已经发送了UDP数据包,服务器正确解析了该数据包并创建了一个线程。然后程序正在等待...

几天使我感到困惑,有人可以帮助我解决它吗? :)。谢谢!

编辑

客户

**不能**工作

for (int i = 0; i < 30; i++) {
    Thread writerWorker = new WriterWorker(socket);
    writerWorker.start();
    Thread readerWorker = new ReaderWorker(socket);
    readerWorker.start();
}

**可以进行工作

for (int i = 0; i < 30; i++) {
    Date d = new Date(); 
    String content = d.toString(); 
    byte[] data = content.getBytes();
    sendPacket = new DatagramPacket(data, data.length, address, serverPort);
    socket.send(sendPacket);
    Thread.sleep(10);
    Thread readerWorker = new ReaderWorker(socket);
    readerWorker.start();
}

WriterWorker

public class WriterWorker extends Thread {
    DatagramSocket socket;
    String serverHost = "localhost";
    int serverPort = 10000;
    DatagramPacket sendPacket;

    public WriterWorker(DatagramSocket socket) {
        this.socket = socket;
    }

    @Override
    public void run() {
        try {
            InetAddress address = InetAddress.getByName(serverHost);
            Date d = new Date();
            String content = d.toString();
            byte[] data = content.getBytes();
            sendPacket = new DatagramPacket(data, data.length, address, serverPort);
            socket.send(sendPacket);
            System.out.println("already send time");

        } catch (Exception e) {
            // TODO: handle exception
        }
    }
}

2 个答案:

答案 0 :(得分:1)

您的逻辑中存在缺陷,当您执行socket.receive(receivedPacket);时,这将使工作人员等待直到某些数据报文包到达为止...

通过套接字处理异步通信的正确方法如下(这里是客户端示例)

socket = new DatagramSocket();
Thread readerWorker = new ReaderWorker(socket);
readerWorker.start();

Thread writerWorker = new WriterWorker(socket);
writerWorker.start();

那样,您可以将读取和写入操作分开,而阻塞方法socket.receive(...)不会停止您的写入线程...

每个工作人员都会实现自己的工作人员循环

写者循环:

while(true){
    if (sendPacket!= null){
        socket.send(sendPacket);
    }
    Thread.sleep(10);
}

阅读器循环:

while(true){
    socket.receive(receivedPacket);
    handlePacket(receivedPacket);
}

注意:

该代码完全是出于我的想法而编写的,我没有检查正确的语法

答案 1 :(得分:0)

在客户端中删除“ Thread.sleep(10)”