假设我们有一个html，如下所示：
<span title="Sports Football">Football</span>
<span title="Sports Badminton">Tennis</span>
<span title="Sports Ski Jump">Ski Jump</span>
如果它包含title，我想提取Sports属性上的参数：
所以最后我们有了一个变量sports：
sports = ['Football', 'Badminton', 'Ski Jump']
这就是我用的：
sports = soup.find_all('span', {'title': 'Sports'})
我什么都没有
答案 0 :(得分：1)
如果$username = "domain\administrator"
$password = "Your password"
$credential = New-Object System.Management.Automation.PSCredential -ArgumentList $username, $password
$computers = Get-ADComputer -Filter *
foreach($computer in $computers){
$computerDNS = $computer.DNSHostName
$hotspot = Invoke-Command -ComputerName $computerDNS -credential $credential -scriptblock {
$hotspot = Get-Service "icssvc"
if($hotspot.Status -eq "Running"){
Write-Host "Hotspot is turned on on $env:computername" -ForegroundColor Red
try{
Start-Service "icssvc"
Write-Host "Successfully stopped service on $env:computername" -ForegroundColor Green
}catch{
Write-Host "Unable to stop service on $env:computername" -ForegroundColor Red
}
}else{
Write-Host "No Hotspot running on $env:computername" -ForegroundColor Green
}
}
}
属性的第一部分是re.compile，则可以将BeautifulSoup与span一起使用来查找所有title标签：
"Sports"输出：
content = """
<span title="Sports Football">Football</span>
<span title="Sports Badminton">Tennis</span>
<span title="Sports Ski Jump">Ski Jump</span>
"""
import re
from bs4 import BeautifulSoup as soup
d = soup(content, 'html.parser')
results = [i.text for i in d.find_all('span', {'title':re.compile('^Sports\s')})]
答案 1 :(得分：0)
您一无所获，因为没有固定的标题仅命名为Sports，而且它的工作方式不像通配符。如果要获取title的属性值，可以在使用get(attr_name)获得的标记对象上使用find_all。
from bs4 import BeautifulSoup
html = '''<span title="Sports Football">Football</span>
<span title="Sports Badminton">Tennis</span>
<span title="Sports Ski Jump">Ski Jump</span>'''
soup = BeautifulSoup(html,"lxml")
title = [s.get('title') for s in soup.find_all('span')]
title
>> ['Sports Football', 'Sports Badminton', 'Sports Ski Jump']
除此之外，如果只需要该元素的文本，则只需对.text中标记对象使用find_all方法即可。
sports = [s.text for s in soup.find_all('span')]
sports
>>['Football', 'Tennis', 'Ski Jump']
答案 2 :(得分：-1)
也许您给出的示例只是在您的头顶上编成的，但是您的跨度内容完全符合您要查找的内容-因此在该示例中，您可以通过以下方法解决：
sports = soup.find_all('span', {'title': 'Sports'}).contents
这将为您提供所需的字符串版本。