Question

这个问题与此处的插件有关：http://www.datatables.net/usage/columns

var hidecols = '{"sClass": "Hide", "aTargets": [0]},{"sClass": "asdf", "aTargets": [1]},{"sClass": "qwer", "aTargets": [2]}';

var hidecolsobj = eval('(' + hidecols + ')');


        var oTable = $('#MainContent_OverviewTable').dataTable({
            "sPaginationType": "full_numbers",
            "bProcessing": true,
            "bServerSide": true,
            "aoColumnDefs":
            [
                hidecolsobj, // <--------- *** HERE ***
            ],
            "sAjaxSource": "Services/Service.svc/GetDataTableOutputOverview",
            "fnServerData": function (sSource, aoData, fnCallback) {
                var jsonAOData = JSON.stringify(aoData);
                $.ajax({
                    type: "POST",
                    async: true,
                    url: sSource,
                    contentType: "application/json; charset=utf-8",
                    data: '{"Input":' + jsonAOData + '}',
                    dataType: "json",
                    success: function (msg) {
                        fnCallback(msg);
                    },
                    error: function (XMLHttpRequest, textStatus, errorThrown) {
                        alert(XMLHttpRequest.status);
                        alert(XMLHttpRequest.responseText);
                    }
                });
            }
        });

因此代码工作正常，没有错误，但类“qwer”是唯一一个应用于我的表。我测试了它，它只应用我的对象列表中最后出现的类。我希望每个列都有hidecols变量中定义的类。我怎么能这样做？

这是它在Datatables网站的文档中的显示方式：

$('#example').dataTable( {
    "aoColumnDefs": [ 
        { "sClass": "my_class", "aTargets": [ 0 ] }
    ]
} );

编辑：

            "aoColumnDefs":
            [
                { "sClass": "Hide", "aTargets": [0] },
                { "sClass": "asdf", "aTargets": [1] }, 
                { "sClass": "qwer", "aTargets": [2] }
            ],

以上编辑工作正常，但这不适合我。我需要能够动态构建字符串hidecols。

Answer 1

您正在为DataTables传递aoColumnDefs参数的字符串。只需删除hidecols“string”周围的引号，使其成为一个对象数组。这将消除对邪恶（eval）的需要。

var hidecols = [{"sClass": "Hide", "aTargets": [0]},{"sClass": "asdf", "aTargets": [1]},{"sClass": "qwer", "aTargets": [2]}];

阿伦

Answer 2

啊！我想出了怎么做！

而不是这样做：

        "aoColumnDefs":
        [
            hidecolsobj, // <--------- *** HERE ***
        ],

我应该这样做：

    var hidecols = '[{"sClass": "Hide", "aTargets": [0]},{"sClass": "asdf", "aTargets": [1]},{"sClass": "qwer", "aTargets": [2]}]';
var hidecolsobj = eval('(' + hidecols + ')');
            "aoColumnDefs": hidecolsobj, // <--------- *** HERE ***

从字符串创建javascript对象以用于数据表

2 个答案: