在https://symfony.com/doc/current/console.html#testing-commands中 用户可以看到如何使用单元测试来测试命令。
问题在于,执行此过程后,将无法测试通过Monolog进行的控制台输出。
$output = $commandTester->getDisplay();
# Returns ''
因此,在$ output上的所有断言都是假的。
有人知道如何在Symfony 4的Symfony命令中对Monolog输出进行单元测试吗?
答案 0 :(得分:0)
我设法通过在monolog“ config / packages / test / monolog.yaml”中添加TestHandler来测试Monolog输出
monolog:
handlers:
test:
type: test
level: debug
这是我的TestClass中的代码
class MyClassCommandTest extends KernelTestCase
{
/**
* First validation tests all invalid options
*/
public function testMyCommand()
{
$kernel = static::createKernel();
$application = new Application($kernel);
$command = $application->find('my:command:name');
$commandTester = new CommandTester($command);
$options['command'] = $command->getName();
$commandTester->execute([
'option_name' => 'value'
], [
'verbosity' => OutputInterface::VERBOSITY_VERY_VERBOSE
]);
//I injected the logger inside my command and added a function getLogger to access it
$logger = $command->getLogger();
$handlers = $logger->getHandlers();
$logs = null
foreach ($handlers as $handler) {
if ($handler instanceof TestHandler) {
$logs = $handler;
}
}
$this->assertTrue($logs->hasRecordThatContains('ERROR_STRING_1', Logger::ERROR), 'Missing Error');
$this->assertTrue($logs->hasRecordThatContains('CRITICAL_STRING_1', Logger::CRITICAL), 'Missing Critical Error');
$this->assertFalse($logs->hasRecordThatContains('SUCCESS_STRING_1', Logger::INFO), 'Has Success Message');
}
}
有人对如何验证输出有其他建议吗?