Question

qualifier_2 = {'KKR' : {'Chris Lynn': 4, 
                      'Sunil Narine': 10, 
                      'Gautam Gambhir (c)': 12, 
                      'Robin Uthappa (wk)': 1, 
                      'Ishank Jaggi': 28, 
                      'Colin Grandhomme': 0,
                      'Suryakumar Yadav': 31,
                      'Piyush Chawla': 2,
                      'Nathan Coulter-Nile': 6,
                      'Umesh Yadav': 2,
                      'Ankit Rajpoot': 4,
                      'Extra runs': 7,
                      'Total batted': 10},
                'MI': {'Lendl Simmons': 3,
                      'Parthiv Patel (wk)': 14,
                      'Ambati Rayudu': 6,
                      'Rohit Sharma (c)': 26,
                      'Krunal Pandya': 45,
                      'Kieron Pollard': 9,
                      'Extra runs': 8,
                      'key-valueal batted': 6}
              }

这是嵌套字典，我想删除某个键值对，并且想要所有分数的总和。

Answer 1

我认为这是最快的解决方案，没有循环：

summ_KRR = sum(qualifier_2['KKR'].values()) # sum of 'KRR'
sum_all = sum(map(lambda x: sum(qualifier_2[x].values()),qualifier_2.keys())) # all sum 
qualifier_2.pop('KKR', None) # delete 'KRR'
print('sum:{}'.format(summ_KRR))
print(qualifier_2)

Answer 2

删除键/值对：

key_to_remove = 'Krunal Pandya'

for key in qualifier_2:
    inner_dict = qualifier_2[key]
    if key_to_remove in inner_dict:
        del inner_dict[key_to_remove]
        break

键值汇总：

total = sum([val for outer_key in qualifier_2 
                     for __, val in qualifier_2[outer_key].items()])

测试删除：

import pprint
pprint.pprint(qualifier_2)        # after removing 'Krunal Pandya'

输出：

{'KKR': {'Ankit Rajpoot': 4,
         'Chris Lynn': 4,
         'Colin Grandhomme': 0,
         'Extra runs': 7,
         'Gautam Gambhir (c)': 12,
         'Ishank Jaggi': 28,
         'Nathan Coulter-Nile': 6,
         'Piyush Chawla': 2,
         'Robin Uthappa (wk)': 1,
         'Sunil Narine': 10,
         'Suryakumar Yadav': 31,
         'Total batted': 10,
         'Umesh Yadav': 2},
 'MI': {'Ambati Rayudu': 6,
        'Extra runs': 8,
        'Kieron Pollard': 9,
        'Lendl Simmons': 3,
        'Parthiv Patel (wk)': 14,
        'Rohit Sharma (c)': 26,
        'key-valueal batted': 6}}

测试求和：

print(total)        # with original qualifier_2

输出：

删除嵌套字典中的键值对并找到键值的总和

2 个答案: