Question

我正在处理一些我存储在数组中的PHP输入，然后将其发布到需要JSON对象数组的API。发布下面的数据时，我总是收到错误消息。

请协助？

数组正在尝试发布

$children = ["child_name" => $cName , "child_dob" => $cDob]; 
dd($children);

转储后在浏览器中输出

array:2 [
  "child_name" => array:5 [
    0 => "Child 1"
    1 => "mnmnmn"
    2 => "mnmnmnm"
    3 => "nbnbnb"
    4 => "nbjhjgkgjhkg"
  ]
  "child_dob" => array:5 [
    0 => "2018-11-01"
    1 => "2018-11-02"
    2 => "2018-11-09"
    3 => "2018-11-14"
    4 => "2018-11-08"
  ]
]

需要从POST提取来自API的数据

{
"children":[
    {"child_name":"abc","child_dob":"23-05-2015"}
  ]
}

Answer 1

问题是您有一个名称和DOB数组，使用foreach()可以很容易地通过遍历名称并添加相应的DOB来创建之后的输出...

$cName = ["Child 1", "cchild 2"];
$cDob = ["2018-01-01", "2018-02-02"];

$children = [];
foreach ( $cName as $key => $name ) {
    $children[] = ["child_name" => $name , "child_dob" => $cDob[$key]];
}

echo json_encode([ "children" => $children], JSON_PRETTY_PRINT););

导致...

{
    "children": [
        {
            "child_name": "Child 1",
            "child_dob": "2018-01-01"
        },
        {
            "child_name": "cchild 2",
            "child_dob": "2018-02-02"
        }
    ]
}

Answer 2

Nigel Ren已经回答了这个问题。

但是对于那些想要以更加实用的PHP编程风格编写解决方案的人。我试图通过声明式而非命令式来解决这个问题。

<?php
$cName = array('Child 1', 'Child 2', 'Child 3');    
$cDob = array('2018-11-01', '2018-11-02', '2018-11-03');

function mapChildNameToDob($childName,  $dob)
{
    return array(
        'child_name' => $childName, 
        'child_dob' => $dob
    );
}

$children['children'] = array_map("mapChildNameToDob", $cName, $cDob );     
echo json_encode($children);

或者，如果您想使用匿名回调函数，则可以这样编写：

<?php
$cName = array('Child 1', 'Child 2', 'Child 3');
$cDob = array('2018-11-01', '2018-11-02', '2018-11-03');

$children['children'] = array_map(function($childName,  $dob) {
    return array(
        'child_name' => $childName, 
        'child_dob' => $dob
    ); 
}, $cName, $cDob ); 

echo json_encode($children);

发出将PHP数组发布到需要JSON对象数组的API的问题

2 个答案: