列出项目:
'Cam218-10-03_16_05-21-54.jpg',
'Cam318-10-03_17_04-21-54.jpg',
'Cam418-10-03_16_04-21-54.jpg',
'Cam218-10-02_16_05-21-54.jpg',
'Cam318-10-02_17_04-21-54.jpg',
'Cam418-10-02_16_04-21-54.jpg',
'Cam218-10-02_16_04-08-31.jpg',
'Cam318-10-02_16_04-08-30.jpg',
'Cam418-10-02_16_04-08-30.jpg',
'Cam518-10-02_16_04-08-35.jpg',
'Cam618-10-02_16_04-08-36.jpg',
'Cam118-10-02_16_04-08-36.jpg',
'Cam118-10-03_16_05-21-54.jpg',
'Cam218-10-03_16_05-21-54.jpg',
'Cam118-10-03_16_05-21-54.jpg',
'Cam118-10-03_16_04-08-31.jpg',
使用python,如何使用时间戳对其进行排序?我希望输出为:
'Cam118-10-03_16_04-08-31.jpg',
'Cam218-10-02_16_04-08-31.jpg',
'Cam318-10-02_16_04-08-30.jpg',
'Cam418-10-02_16_04-08-30.jpg',
'Cam518-10-02_16_04-08-35.jpg',
'Cam618-10-02_16_04-08-36.jpg',
我已经尝试过了:
file=open("ram.txt","r")
data=file.readlines()
data.sort()
for i in data:
print(i,end='')
答案 0 :(得分:0)
file=open("ram.txt","r")
data=file.readlines() #assuming data now has the images in a list
dates = []
for img in data:
img = img.split('-')[1] #remove the cam118 etc and just get date strings
dates.append(img)
zipped_pairs = zip(dates, data) #zip them together
sorted_dates = [x for _, x in sorted(zipped_pairs, reverse=True)]