Question

我需要在sql查询中使用like运算符来检查数据库记录中另一个文本中的文本单词，以查找类似该文本单词的任何记录例如：

my text is : ajax,net,apache,sql

and records like : 

assembly,c#,java,apache
ajax,pascal,c,c++
...

我需要查询以查找任何包含我的文字的行

此图片是搜索输入

我将在搜索字符串中找到任何包含单词的行

        SELECT
        dbo.tblProjects.id, dbo.tblProjects.prTitle, dbo.tblUsers.id AS UserID,tblUsers.nickname, 
        dbo.tblProjects.prTags, dbo.tblProjects.prDesc, dbo.tblProjects.prFaDate
    FROM
        dbo.tblUsers 
    INNER JOIN
        dbo.tblProjects ON dbo.tblUsers.id = dbo.tblProjects.UserID

    where (tblUsers.id=@userid)and(dbo.tblProjects.tags like @userskills + '%')

    order by dbo.tblProjects.id desc

萨米语更新

ALTER procedure [dbo].[Dashboard_My_Skills_Projects]
(
  @userid bigint,
  @userskills nvarchar(100)
)
as
begin
    SELECT T.id, 
           T.prTitle, 
           U.id AS [UserID],
           U.nickname,
           T.prTags, 
           T.prDesc, 
           T.prFaDate

    FROM dbo.tblUsers U INNER JOIN dbo.tblProjects T ON U.id = T.UserID
    WHERE U.id = @userid
          AND
          T.tags IN(
                     SELECT tags
                     FROM dbo.tblProjects T1 CROSS JOIN 
                                  (
                                    SELECT Value 
                                    FROM STRING_SPLIT(@userskills, ',')
                                  ) TT
                     WHERE T1.tags LIKE '%' + Value + '%'
                   )


    order by T.id desc


end

tblUsers

tblProjects

Answer 1

您可以将CROSS APPLY，STRING_SPLIT()和LIKE用作

  CREATE TABLE T(
  Tags VARCHAR(100)
);

INSERT INTO T VALUES
('Analytics,Amazon Web Service,Active Directory'),
('BMC Remedy,Big Data,Ajax'),
('Azure,Assembly,Appache'),
('Azure,Assembly,Appache'),
('Azure,Assembly,Appache'),
('Azure,Assembly,Appache'),
('Apple Safari,Analytics,Ajax');

DECLARE @Search VARCHAR(45) = 'Active Directory,Ajax,Azure';

SELECT DISTINCT Tags
FROM T CROSS APPLY (SELECT Value FROM STRING_SPLIT(@Search, ',')) TT
WHERE Tags LIKE '%' + Value + '%';

返回：

+-------------------------------------------------+
|                      Tags                       |
+-------------------------------------------------+
| Analytics, Amazon Web Service, Active Directory |
| Apple Safari, Analytics, Ajax                   |
| Azure, Assembly, Appache                        |
| BMC Remedy, Big Data, Ajax                      |
+-------------------------------------------------+

Demo

注意： STRING_SPLIT() 功能仅在2016+版本上可用，因此如果您不使用2016+版本，则需要创建自己的功能。

更新

CREATE TABLE Tags(
  Tags VARCHAR(100),
  UserID INT
);

CREATE TABLE Users(
  UserID INT,
  UserName VARCHAR(45)
 );

INSERT INTO Tags VALUES
('Analytics,Amazon Web Service,Active Directory', 1),
('BMC Remedy,Big Data,Ajax', 2),
('Azure,Assembly,Appache', 3),
('Azure,Assembly,Appache', 1),
('Azure,Assembly,Appache', 4),
('Azure,Assembly,Appache', 2),
('Apple Safari,Analytics,Ajax', 1);

INSERT INTO Users VALUES
(1, 'User1'),
(2, 'User2'),
(3, 'User3'),
(4, 'User4');

DECLARE @Search VARCHAR(45) = 'Active Directory,Azure',
        @UserID INT = 1;

SELECT U.UserID,
       U.UserName,
       T.Tags Skills
FROM Users U INNER JOIN Tags T ON U.UserID = T.UserID
WHERE U.UserID = @UserID
      AND
      T.Tags IN(
                 SELECT Tags
                 FROM Tags T1 CROSS JOIN 
                              (
                                SELECT Value 
                                FROM STRING_SPLIT(@Search, ',')
                              ) TT
                 WHERE T1.Tags LIKE '%' + Value + '%'
               )

Here is a live demo

和 here is your stored procedure works just fine and as expected

Answer 2

Like将在列中搜索指定的模式。

并在评论中注明@Pedro。.我希望您不要只在1条记录中做到这一点。

您可以使用

SELECT * 
FROM your_table
WHERE your_text LIKE '%ac%';

您可以在Here中了解有关Like运算符的更多信息

编辑：

您可以使用String_Split功能

SELECT
   *
FROM
   table
WHERE
   EXISTS (SELECT 
              *  
           FROM 
              STRING_SPLIT(Tags, ',')  
           WHERE 
              value IN ('Active Directory', 'Ajax', 'Azure')

Answer 3

首次创建功能

Create FUNCTION fn_SplitADelimitedList
(
   @String NVARCHAR(MAX)
)
   RETURNS @SplittedValues TABLE(
   Value nvarchar(500)
   )
As
 BEGIN
      DECLARE @SplitLength INT
      DECLARE @Delimiter VARCHAR(10) 
      SET @Delimiter = ','

      WHILE len(@String) > 0
      BEGIN
           SELECT @SplitLength = (CASE charindex(@Delimiter, @String)
           WHEN 0 THEN
           datalength(@String) / 2
           ELSE
           charindex(@Delimiter, @String) - 1
           END)

       INSERT INTO @SplittedValues
            SELECT cast(substring(@String, 1, @SplitLength) AS nvarchar(50))
            WHERE
            ltrim(rtrim(isnull(substring(@String, 1, @SplitLength), ''))) <> '';
            SELECT @String = (CASE ((datalength(@String) / 2) - @SplitLength)
            WHEN 0 THEN
            ELSE
            right(@String, (datalength(@String) / 2) - @SplitLength - 1)
            END)
      END
 RETURN
END

然后像这样查询

DECLARE @yourtext NVARCHAR(400) = 'Apple, Active Directory'
SELECT 
LTRIM(RTRIM(c.Value)),
em.tags
FROM tblTest em
CROSS APPLY fn_SplitADelimitedList(em.tags) c
inner join 
(SELECT Split.a.value('.', 'NVARCHAR(MAX)') DATA
FROM
(
SELECT CAST('<X>'+REPLACE(@yourtext, ',', '</X><X>')+'</X>' AS XML) AS String
) AS A
CROSS APPLY String.nodes('/X') AS Split(a)) v 
on LTRIM(RTRIM(c.Value)) = LTRIM(RTRIM(v.DATA))

如何在SQL中使用like运算符在另一个文本上的文本中找到一些单词

3 个答案:

首次创建功能

然后像这样查询