Question

所以我的任务是计算一些简单的KPI。

我已经积累了需要的所有数据的视图。

 Year_CW    Is Started      Needs Help
 -------------------------------------
 2018/45       0              1
 2018/43       1              1
 2018/45       0              1
 2018/42       1              0
 2018/45       0              1
 2018/45       1              1
 2018/41       0              1
 2018/43       0              0
 2018/45       1              1
 2018/45       0              0

然后我写了以下查询：

SELECT DISTINCT YEAR_CW 
FROM TestView
ORDER BY YEAR_CW DESC

哪个返回此

Year_CW
--------
2018/45
2018/44
2018/43
2018/42

我现在想为Year_CW的每行计数一次，其他两行分别为1和0。这可能是一个非常简单的问题，但是我只是从SQL开始，我真的不知道基于外部查询的查询的关键字是什么。

其他查询将是

Select Count(Is Started)
from Testview
Where Is Started = 1

以此类推。但是我真的不知道如何将它们放在一起并基于第一个查询。

感谢您的帮助。

Answer 1

您似乎想要条件聚合：

select Year_CW,
       sum(case when col = 1 then 1 else 0 end) as one_count,
       sum(case when col = 0 then 1 else 0 end) as zero_count
from (select Year_CW, IsStarted as col
      from TestView tv
      union all
      select Year_CW, NeedsHelp
      from TestView tv
     ) tv
group by Year_CW
order by Year_CW desc;

Answer 2

select Year_CW
, sum(case when Is_Started = 1 then 1 end) as Is_Started_1
, sum(case when Is_Started = 0 then 1 end) as Is_Started_0
, sum(case when Needs_Help = 1 then 1 end) as Needs_Help_1
, sum(case when Needs_Help = 0 then 1 end) as Needs_Help_0
from Test_View 
group by Year_CW

所以我是怎么做的，我为您创建了4个新字段。首先是为“ Is_Started = 1”的每个字段赋予值“ 1”，然后对这些实例求和。对于“ Needs_Help”列，我对0值做了同样的处理，对值1和0做了另外两个字段。我相信这会给您您想要的结果。

Answer 3

因此，如果我对问题的理解正确，那么您只是在寻找Year_CW字段的另外两列SUM中的GROUP BY。就是这样。

SELECT Year_CW, SUM([Is Started]), SUM([Needs Help])
FROM TestView
GROUP BY Year_CW

Answer 4

如果只有0或1，则可以将0或1加起来。

SELECT YEAR_CW, 
SUM("Is Started") AS TotalStarted,
SUM(1 - "Is Started") AS TotalNotStarted,
SUM("Needs Help") AS TotalNeedsHelp,
SUM(1 - "Needs Help") AS TotalNoHelpNeeded
FROM TestView
GROUP BY YEAR_CW
ORDER BY YEAR_CW DESC

用另一行的每个不同条目对具有特定条目的行进行计数

4 个答案: