AssertValidName抛出一个大概由库本身生成的名称

时间：2018-11-21 13:04:26

标签： java graphql-java graphql-spqr

这使用了非常复杂的实体集合，该实体集合主要由JPA实体组成，但也包括代理和从API提取的实体。我只是用@GraphQLQuery批注真正地注释了要尝试获取的基类，但是它进入了下面的层次结构，并在某个时候找到了一个静态HashMap<String, String[]>且具有硬编码的属性。内容。 （我学会了不问...）此时，它引发了此异常，并且一切都停止了：

graphql.AssertException: Name must be non-null, non-empty and match [_A-Za-z][_0-9A-Za-z]* - was 'Map_String_String[]Scalar'
at graphql.Assert.assertValidName(Assert.java:58)
at graphql.schema.GraphQLScalarType.<init>(GraphQLScalarType.java:50)
at graphql.schema.GraphQLScalarType.<init>(GraphQLScalarType.java:45)
at io.leangen.graphql.util.Scalars.graphQLMapScalar(Scalars.java:325)
at io.leangen.graphql.generator.mapping.common.ObjectScalarAdapter.toGraphQLType(ObjectScalarAdapter.java:20)
at io.leangen.graphql.generator.mapping.common.ObjectScalarAdapter.toGraphQLType(ObjectScalarAdapter.java:16)
at io.leangen.graphql.generator.mapping.common.CachingMapper.toGraphQLType(CachingMapper.java:30)
at io.leangen.graphql.generator.OperationMapper.toGraphQLType(OperationMapper.java:179)
at io.leangen.graphql.generator.OperationMapper.toGraphQLType(OperationMapper.java:165)
at io.leangen.graphql.generator.OperationMapper.toGraphQLField(OperationMapper.java:138)
at io.leangen.graphql.generator.mapping.common.ObjectTypeMapper.lambda$getFields$3(ObjectTypeMapper.java:88)
at java.util.stream.ReferencePipeline$3$1.accept(ReferencePipeline.java:193)
at java.util.HashMap$ValueSpliterator.forEachRemaining(HashMap.java:1625)
at java.util.stream.AbstractPipeline.copyInto(AbstractPipeline.java:481)
at java.util.stream.AbstractPipeline.wrapAndCopyInto(AbstractPipeline.java:471)
at java.util.stream.ReduceOps$ReduceOp.evaluateSequential(ReduceOps.java:708)
at java.util.stream.AbstractPipeline.evaluate(AbstractPipeline.java:234)
at java.util.stream.ReferencePipeline.collect(ReferencePipeline.java:499)
at io.leangen.graphql.generator.mapping.common.ObjectTypeMapper.getFields(ObjectTypeMapper.java:89)
at io.leangen.graphql.generator.mapping.common.ObjectTypeMapper.toGraphQLType(ObjectTypeMapper.java:41)
at io.leangen.graphql.generator.mapping.common.ObjectTypeMapper.toGraphQLType(ObjectTypeMapper.java:33)
at io.leangen.graphql.generator.mapping.common.CachingMapper.toGraphQLType(CachingMapper.java:30)
at io.leangen.graphql.generator.OperationMapper.toGraphQLType(OperationMapper.java:179)
at io.leangen.graphql.generator.OperationMapper.toGraphQLType(OperationMapper.java:165)
at io.leangen.graphql.generator.OperationMapper.toGraphQLField(OperationMapper.java:138)
at io.leangen.graphql.generator.mapping.common.ObjectTypeMapper.lambda$getFields$3(ObjectTypeMapper.java:88)
at java.util.stream.ReferencePipeline$3$1.accept(ReferencePipeline.java:193)
at java.util.HashMap$ValueSpliterator.forEachRemaining(HashMap.java:1625)
at java.util.stream.AbstractPipeline.copyInto(AbstractPipeline.java:481)
at java.util.stream.AbstractPipeline.wrapAndCopyInto(AbstractPipeline.java:471)
at java.util.stream.ReduceOps$ReduceOp.evaluateSequential(ReduceOps.java:708)
at java.util.stream.AbstractPipeline.evaluate(AbstractPipeline.java:234)
at java.util.stream.ReferencePipeline.collect(ReferencePipeline.java:499)
at io.leangen.graphql.generator.mapping.common.ObjectTypeMapper.getFields(ObjectTypeMapper.java:89)
at io.leangen.graphql.generator.mapping.common.ObjectTypeMapper.toGraphQLType(ObjectTypeMapper.java:41)
at io.leangen.graphql.generator.mapping.common.ObjectTypeMapper.toGraphQLType(ObjectTypeMapper.java:33)
at io.leangen.graphql.generator.mapping.common.CachingMapper.toGraphQLType(CachingMapper.java:30)
at io.leangen.graphql.generator.OperationMapper.toGraphQLType(OperationMapper.java:179)
at io.leangen.graphql.generator.OperationMapper.toGraphQLType(OperationMapper.java:165)
at io.leangen.graphql.generator.OperationMapper.toGraphQLField(OperationMapper.java:138)
at io.leangen.graphql.generator.OperationMapper.lambda$generateQueries$0(OperationMapper.java:91)
at java.util.stream.ReferencePipeline$3$1.accept(ReferencePipeline.java:193)
at java.util.ArrayList$ArrayListSpliterator.forEachRemaining(ArrayList.java:1382)
at java.util.stream.AbstractPipeline.copyInto(AbstractPipeline.java:481)
at java.util.stream.AbstractPipeline.wrapAndCopyInto(AbstractPipeline.java:471)
at java.util.stream.ReduceOps$ReduceOp.evaluateSequential(ReduceOps.java:708)
at java.util.stream.AbstractPipeline.evaluate(AbstractPipeline.java:234)
at java.util.stream.ReferencePipeline.collect(ReferencePipeline.java:499)
at io.leangen.graphql.generator.OperationMapper.generateQueries(OperationMapper.java:92)
at io.leangen.graphql.generator.OperationMapper.<init>(OperationMapper.java:75)
at io.leangen.graphql.GraphQLSchemaGenerator.generate(GraphQLSchemaGenerator.java:868)
at com.ist.exam.graphql.services.GraphQLService.init(GraphQLService.java:27)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:498)
at org.springframework.beans.factory.annotation.InitDestroyAnnotationBeanPostProcessor$LifecycleElement.invoke(InitDestroyAnnotationBeanPostProcessor.java:349)
at org.springframework.beans.factory.annotation.InitDestroyAnnotationBeanPostProcessor$LifecycleMetadata.invokeInitMethods(InitDestroyAnnotationBeanPostProcessor.java:300)
at org.springframework.beans.factory.annotation.InitDestroyAnnotationBeanPostProcessor.postProcessBeforeInitialization(InitDestroyAnnotationBeanPostProcessor.java:133)
... 39 more

我不知道该名称是如何生成的，但是它以“ Map_String_String [] Scalar”的形式出现，然后抛出assertValidName。

我会用@GraphQLQuery(name="somethingClever")注释该属性，但目前我们在整个公司共享的库中，并且在此处进行的更改必须经过更改请求和更改。

我尝试用withBasePackages排除此代理程序包，但这似乎没有效果。这是尝试创建模式的方法：

GraphQLSchema schema = new GraphQLSchemaGenerator()
                    .withBasePackages("entities")
                    .withResolverBuilders(new AnnotatedResolverBuilder())
                    .withOperationsFromSingleton(examService)
                    .withValueMapperFactory(new JacksonValueMapperFactory())
                    .generate();
            graphQL = GraphQL.newGraphQL(schema).build();

有人以前见过这些问题吗？我可以将软件包列入黑名单而不是将其列入白名单吗？例如withBasePackages("!proxies")

1 个答案:

答案 0 :(得分：2)

它是a bug，因为永远不会生成一个无效的名称。我将在GraphQL SPQR的下一版本中立即解决此问题（在撰写本文时，当前版本为0.9.9）。

关于它最终如何变成Map_String_String[]Scalar，这确实涉及……地图异常棘手，因为GraphQL中没有地图。这些选项基本上是将地图视为类型化的键/值对的列表，或仅视为未知的动态结构（即 JSON标量）。 SPQR支持两种方法，但默认情况下会将地图视为复杂（JSON）标量。为了保持对内部内容的某种了解，它将为每种基础Java类型生成一个名称不同的标量。为此，它必须为每个生成唯一的名称。对于您而言，它会找到一个Map<String, String[]>，它会生成您看到的无效名称-Map_String_String[]Scalar。

您可以通过注册一个可以捕获这种情况的自定义TypeMapper或与此相关的所有复杂标量，并为其赋予相同的名称而不是唯一的名称来轻松解决此问题。

例如

public class CustomObjectScalarMapper extends ObjectScalarMapper {
    private static final String OBJECT_SCALAR_NAME = "ObjectScalar";

    @Override
    protected String getTypeName(AnnotatedType type, BuildContext buildContext) {
        return OBJECT_SCALAR_NAME;
    }

    @Override
    protected String getInputTypeName(AnnotatedType type, BuildContext buildContext) {
        return OBJECT_SCALAR_NAME;
    }
}

并通过以下方式替换现有的ObjectScalarMapper：

generator.withTypeMappers((conf, current) -> current.replace(ObjectScalarMapper.class, new CustomObjectScalarMapper()))

这样，所有复杂的标量都将称为ObjectScalar，而您将不会遇到问题。

如果您希望更详细一点，也可以覆盖supports方法。

一句话，您的生成器配置不需要将一堆东西设置为其默认值。

GraphQLSchema schema = new GraphQLSchemaGenerator()
                    .withBasePackages("entities")
                    .withResolverBuilders(new AnnotatedResolverBuilder())
                    .withOperationsFromSingleton(examService)
                    .withValueMapperFactory(new JacksonValueMapperFactory())
                    .generate();

等同于

GraphQLSchema schema = new GraphQLSchemaGenerator()
                    .withBasePackages("entities")
                    .withOperationsFromSingleton(examService)
                    .generate();
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